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anonymous
 one year ago
Can anyone help with this question!
anonymous
 one year ago
Can anyone help with this question!

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aaronq
 one year ago
Best ResponseYou've already chosen the best response.2if dont have the formulas in your notes, just dimensional analysis to match the units

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have the formula but not sure how to complete part C, D or F

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would you be able to show me how to do it?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2for C) you're just diluting the initial concentration by half, so instead of 0.13 M you have 0.65 M, D) is the same thing as A) For F) find the rotation of each enantiomer separately, then subtract the rotation of one from the other (from the concentrations, you can see that the D enantiomer will cause more optical effects)

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2post what you have, i'll help you get it right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I cant check if they are right till I fill in all of the blanks

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2is the volume in the cuvette 10 mL?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2cuz i know the path length is 1 dm = 10 cm

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0If you don't mind me asking what level of chemistry is this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First semester of organic chemistry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think the volume is about 2 ml for a cuvette.

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2is that the volume you're using to solve these?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was just converting from M and moles to liters. M= mol/L

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Once I found liters, I plugged the numbers into the equation. Thats how I did the first part.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is what I did: 119/0.130

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2oh right lol so then you just multiplied by the 0.16 degrees? so i think without doing any calculations, for C) is half of the initial rotation, 0.16/2= 0.08 degrees (because half of the amount) for D) it would be half of what you got in A)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do you do part F?

cuanchi
 one year ago
Best ResponseYou've already chosen the best response.2I think the point A) specific rotation = observed rotation / (c*l) l = cell path length in decimeters. (1 decimeter = 1 dm = 10 cm. A standard polarimeter tube is 1.00 dm in length.) c = concentration in g ml1 for a pure liquid compound (i.e., the liquid's density), or g 100 ml1 for a solution. specific rotation = 0.16 deg / c 1 c= 0.130 mol x (119 g/ mol) /1000 mL =0.01547 g/mL specific rotation = 0.16 deg /(0.01547 g/mL x 1 dm) = 10.34 deg mL/g dm B) is correct C) @aaronq said is going to be 1/2 of 0.16 = 0.08 D) I think that the specific rotation of a solution is independent of the concentration and is a intensive property of the solution dependent of the nature of the solute and the solvent. Then I think will be the same that A. The observed rotation is dependent of the concentration. E) the specific rotation will have the same numeric value but different sign that A because is the other enantiomer F) the observed rotation you have to subtract 0.01 moleD  0.005 mol L = 0.005 mol D x 119 g/mol = 0.595 g this is in 100ml observed rotation = specific rotation x concentration x 1 dm observed rotation = 10.34 deg mL/g dm x (0.595 g/100mL mol) observed rotation = 0.06 deg

cuanchi
 one year ago
Best ResponseYou've already chosen the best response.2http://www.chem.ucla.edu/harding/tutorials/stereochem/calcs.html
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