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anonymous
 one year ago
Two mechanics worked on a car. The first mechanic charged $75 per hour, and the second mechanic charged $110 per hour. The mechanics worked for a combined total of 20 hours, and together they charged a total of $2025. How long did each mechanic work?
Will medal
anonymous
 one year ago
Two mechanics worked on a car. The first mechanic charged $75 per hour, and the second mechanic charged $110 per hour. The mechanics worked for a combined total of 20 hours, and together they charged a total of $2025. How long did each mechanic work? Will medal

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so.. let's say hmmm the hours the $75 mechanic worked was \(\bf x\) and the hours the $110 mechanic worked was \(\bf y\) how many hours did they work together?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so... they worked together 20 hours we dunno what those hours are, but we can call them "x" and "y" so we could say that \(\bf x+y=20\) the mechanic that charges $75 per hour, after "x" hours, he ended up charging 75*x or 75x the mechanic that charges $110 per hour, after "y" hours, he ended up charging 110*y or 110y now, their total bill was 2025 so we could also say that \(\bf 75x+110y = 2025\) any ideas?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im confused i have to give hours for mechanic one and mechanic 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have 4 questions like this i really want to know how tp figure them out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes.... notice... x+y = 20 so... if you solve that for say "y"... how does it look like?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the hours, notice above, for each is "x" and "y", thus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is basically a substitution problem involving the 2 equations up above ^^. We have : x + y = 20 > x = y + 20 75x + 110y = 2025 now sub y + 20 in for x back into the second equation....you will then be solving for y, the hrs for the mechanic that charges 110 per hr.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mechanic 1 5 hours mechanic 2 15 hours ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lets check by subbing in your answers into the 2nd equation.. 75x + 110y = 2025 75(5) + 110(15) = 2025 375 + 1650 = 2025 2025 = 2025 (correct) yes...that is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ty for explaining it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0medal should go to jdoe....he/she helped you set it up...without that, you have nothing...lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you stayed to make sure i understood..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all is good...I gave jdoe a medal I am always happy to help when I can :)
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