Two mechanics worked on a car. The first mechanic charged $75 per hour, and the second mechanic charged $110 per hour. The mechanics worked for a combined total of 20 hours, and together they charged a total of $2025. How long did each mechanic work?
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so.. let's say hmmm the hours the $75 mechanic worked was \(\bf x\)
and the hours the $110 mechanic worked was \(\bf y\)
how many hours did they work together?
so... they worked together 20 hours
we dunno what those hours are, but we can call them "x" and "y"
so we could say that
the mechanic that charges $75 per hour, after "x" hours, he ended up charging 75*x or 75x
the mechanic that charges $110 per hour, after "y" hours, he ended up charging 110*y or 110y
now, their total bill was 2025
so we could also say that
\(\bf 75x+110y = 2025\)
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i have to give hours for mechanic one and mechanic 2
i have 4 questions like this i really want to know how tp figure them out
notice... x+y = 20
so... if you solve that for say "y"... how does it look like?
the hours, notice above, for each is "x" and "y", thus
this is basically a substitution problem involving the 2 equations up above ^^.
We have :
x + y = 20 ----> x = -y + 20
75x + 110y = 2025
now sub -y + 20 in for x back into the second equation....you will then be solving for y, the hrs for the mechanic that charges 110 per hr.
mechanic 1 5 hours
mechanic 2 15 hours ??
lets check by subbing in your answers into the 2nd equation..
75x + 110y = 2025
75(5) + 110(15) = 2025
375 + 1650 = 2025
2025 = 2025 (correct)
yes...that is correct
ty for explaining it
medal should go to jdoe....he/she helped you set it up...without that, you have nothing...lol
you stayed to make sure i understood..
all is good...I gave jdoe a medal
I am always happy to help when I can :)