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so.. let's say hmmm the hours the $75 mechanic worked was \(\bf x\) and the hours the $110 mechanic worked was \(\bf y\) how many hours did they work together?
so... they worked together 20 hours we dunno what those hours are, but we can call them "x" and "y" so we could say that \(\bf x+y=20\) the mechanic that charges $75 per hour, after "x" hours, he ended up charging 75*x or 75x the mechanic that charges $110 per hour, after "y" hours, he ended up charging 110*y or 110y now, their total bill was 2025 so we could also say that \(\bf 75x+110y = 2025\) any ideas?
im confused i have to give hours for mechanic one and mechanic 2
i have 4 questions like this i really want to know how tp figure them out
yes.... notice... x+y = 20 so... if you solve that for say "y"... how does it look like?
the hours, notice above, for each is "x" and "y", thus
this is basically a substitution problem involving the 2 equations up above ^^. We have : x + y = 20 ----> x = -y + 20 75x + 110y = 2025 now sub -y + 20 in for x back into the second equation....you will then be solving for y, the hrs for the mechanic that charges 110 per hr.
mechanic 1 5 hours mechanic 2 15 hours ??
lets check by subbing in your answers into the 2nd equation.. 75x + 110y = 2025 75(5) + 110(15) = 2025 375 + 1650 = 2025 2025 = 2025 (correct) yes...that is correct
ty for explaining it
medal should go to jdoe....he/she helped you set it up...without that, you have nothing...lol
you stayed to make sure i understood..
all is good...I gave jdoe a medal I am always happy to help when I can :)