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anonymous

  • one year ago

Multiply. Write the product in simplest form 3/4 (-8/25)(-5/12)

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  1. anonymous
    • one year ago
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    1,10th

  2. anonymous
    • one year ago
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    1 10

  3. anonymous
    • one year ago
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    ( 3 4 ( −8 25 ))( −5 12 ) = 3 4 ( −8 25 )( −5 12 ) = 3 4 ( −8 25 )( −5 12 ) = −6 25 ( −5 12 ) = 1 10 this is it step by step

  4. anonymous
    • one year ago
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    its confusing looking at it like that

  5. Directrix
    • one year ago
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    @mathwiz916 Please come to this thread and explain your work. We cannot understand it. Thanks.

  6. jdoe0001
    • one year ago
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    probably becuause he/she simply copied and pasted it from somewhere as opposed to actually do it and the paste came out out of whack

  7. anonymous
    • one year ago
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    yes i do agree with them

  8. jdoe0001
    • one year ago
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    ahemm \(\bf \cfrac{3}{4}\left( -\cfrac{8}{25} \right)\left( -\cfrac{5}{12} \right)\implies \cfrac{3}{4}\left( \cfrac{-8}{25} \right)\left( \cfrac{-5}{12} \right) \\ \quad \\ \cfrac{3\cdot (-8)\cdot (-5)}{2\cdot 25\cdot 12}\implies \cfrac{\cancel{3}\cdot (-2\cdot 2\cdot \cancel{2})\cdot (-1\cdot \cancel{5})}{\cancel{2}\cdot (\cancel{5}\cdot 5)\cdot (\cancel{3}\cdot 4)}\)

  9. jdoe0001
    • one year ago
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    missed one there... sec

  10. jdoe0001
    • one year ago
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    \(\bf \cfrac{3}{4}\left( -\cfrac{8}{25} \right)\left( -\cfrac{5}{12} \right)\implies \cfrac{3}{4}\left( \cfrac{-8}{25} \right)\left( \cfrac{-5}{12} \right) \\ \quad \\ \cfrac{3\cdot (-8)\cdot (-5)}{2\cdot 25\cdot 12}\implies \cfrac{\cancel{3}\cdot (- 2\cdot \cancel{2}\cdot \cancel{2})\cdot (-1\cdot \cancel{5})}{\cancel{2}\cdot (\cancel{5}\cdot 5)\cdot (\cancel{3}\cdot \cancel{2}\cdot \cancel{2})}\)

  11. jdoe0001
    • one year ago
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    notice 5* 5 = 25 2*2*2= 8 2*2 = 4

  12. jdoe0001
    • one year ago
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    and... ahemm 3*4 or 3*2*2 = 12

  13. anonymous
    • one year ago
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    it should come out as |dw:1444433647692:dw|

  14. anonymous
    • one year ago
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    \[\frac{ 1 }{ 10}\]

  15. anonymous
    • one year ago
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    as the answer

  16. jdoe0001
    • one year ago
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    hmmm

  17. jdoe0001
    • one year ago
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    well.... I missed one again :( at the botom, a 2... lemme do the whole thing

  18. jdoe0001
    • one year ago
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    \(\bf \cfrac{3}{4}\left( -\cfrac{8}{25} \right)\left( -\cfrac{5}{12} \right)\implies \cfrac{3}{4}\left( \cfrac{-8}{25} \right)\left( \cfrac{-5}{12} \right) \\ \quad \\ \cfrac{3\cdot (-8)\cdot (-5)}{2\cdot 25\cdot 12}\implies \cfrac{3\cdot (-2\cdot 2\cdot 2)\cdot ( 5)}{2\cdot (5\cdot 5)\cdot (3\cdot 4)} \\ \quad \\ \cfrac{\cancel{3}\cdot (-1\cdot \cancel{2}\cdot \cancel{2}\cdot \cancel{2})\cdot (-1\cdot \cancel{5})}{\cancel{2}\cdot (\cancel{5}\cdot 5)\cdot (\cancel{3}\cdot \cancel{2}\cdot \cancel{2})}\implies \cfrac{-1\cdot -1}{5} \implies \cfrac{1}{5}\)

  19. Jhannybean
    • one year ago
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    \[\left(\frac{\color{orange}3}{\color{blue}{4}}\right)\left(\frac{\color{blue}{-8}}{\color{red}{25}}\right)\left(\frac{\color{red}{-5}}{\color{orange}{12}}\right)\] \[\left(\frac{1\cancel{\color{orange}3}}{1\cancel{\color{blue}{4}}}\right)\left(\frac{-2\cancel{\color{blue}{-8}}}{-5\cancel{\color{red}{25}}}\right)\left(\frac{1\cancel{\color{red}{-5}}}{4\cancel{\color{orange}{12}}}\right)\] \[=\frac{-2}{-20} \] \[=\frac{1}{10}\]

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