If the slope of the line that passes through the points (a,0) and (1,-2) is 1/2, what is the value of a? @jim_thompson5910

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If the slope of the line that passes through the points (a,0) and (1,-2) is 1/2, what is the value of a? @jim_thompson5910

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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have you applied the slope formula?
\[m=\frac{y_2-y_1}{x_2-x_1} \]
No. I do not know that to do that with this problem.

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well you are given two points on a line and the slope ... which makes me think slope formula since only one of the values is unknown in the pairs given you are given m is 1/2 (x1,y1)=(1,-2) and (x2,y2)=(a,0)
\[\frac{1}{2}=\frac{0-(-2)}{a-1}\] solve for a
a = -2
how did you get that?
0 + 2 is 2 and a - 1 is -1
it might make it easier on you if you flip both sides \[\frac{2}{1}=\frac{a-1}{0-(-2)}\] see if you can solve now
by the way 2/1 is just 2
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ a}}\quad ,&{\color{blue}{ 0}})\quad % (c,d) &({\color{red}{ 1}}\quad ,&{\color{blue}{ -2}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\implies \cfrac{{\color{blue}{ -2}}-{\color{blue}{ 0}}}{{\color{red}{ 1}}-{\color{red}{ a}}}=\cfrac{1}{2}\)
I am confused now.
confused on how to solve 2=(a-1)/2 for a?
Yes.
are confused on the flipping part? confused on the equation we got?
I am confused on solving with A.
solving with A?
what does that mean
you mean solve for a?
The variable is A in the equation
don't we have a not A? \[\frac{1}{2}=\frac{0-(-2)}{a-1} \\ \\ 0-(-2) \text{ is the same as } 2 \\ \text{ you have } \\ \frac{1}{2}=\frac{2}{a-1}\]
you can flip both sides like I did earlier \[\frac{2}{1}=\frac{a-1}{2} \\ \text{ now } \frac{2}{1}=2 \\ 2=\frac{a-1}{2}\]
try to undo that division by 2 ...multiply 2 on both sides
1=4/a-1?
well 2 times 2 is 4 not 1 and how did you put a-1 back in the denominator? also 2/2=1 not 4...
oh you went backwards
it is 1/2 times 2
do you see this equation 2=(a-1)/2 I was asking you multiply this equation by 2 on both sides
this gives you 4=a-1
how did you get 2?
@Jhannybean you can finish i have to leave I'm sorry
I get it now.
\[2=\frac{a-1}{2} \implies 4 = a-1 \implies a= 4+1\]
That is what I got.
Thank you.

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