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mckenzieandjesus

  • one year ago

Graph the data in the table below. Which kind of function best models the data? Write an equation to model the data. quadratic; y = –x2 + 2x – 3 linear; y = – 2x – 3 exponential; y = –3•1.5x quadratic; y = –x2 – 3

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  1. mckenzieandjesus
    • one year ago
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    |dw:1444433891025:dw|

  2. mckenzieandjesus
    • one year ago
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    @jim_thompson5910

  3. jim_thompson5910
    • one year ago
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    what do you have so far (in terms of work)?

  4. mckenzieandjesus
    • one year ago
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    I dont understand how to do it

  5. jim_thompson5910
    • one year ago
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    ok let's say we pick on choice B linear; y = – 2x – 3

  6. jim_thompson5910
    • one year ago
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    IF the answer was choice B, then (0,-3) should lie on the graph so should (1,-2) and (2,-3) etc etc

  7. jim_thompson5910
    • one year ago
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    but what is the value of y when x = 1 y = – 2x – 3 y = -2*1 - 3 y = ??

  8. mckenzieandjesus
    • one year ago
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    -5?

  9. jim_thompson5910
    • one year ago
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    yes so (1,-5) is actually on y = – 2x – 3 not (1,-2)

  10. jim_thompson5910
    • one year ago
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    this eliminates choice B

  11. mckenzieandjesus
    • one year ago
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    ok

  12. jim_thompson5910
    • one year ago
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    test the points with the other equations. You need to make sure all points fit

  13. mckenzieandjesus
    • one year ago
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    so would i do -2*2-3?

  14. mckenzieandjesus
    • one year ago
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    nvrm!

  15. jim_thompson5910
    • one year ago
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    well you could, but we proved B wasn't the answer. So there's no need to check B any more

  16. mckenzieandjesus
    • one year ago
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    got it nvrm lol

  17. jim_thompson5910
    • one year ago
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    alright

  18. mckenzieandjesus
    • one year ago
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    Would the answer be A?

  19. jim_thompson5910
    • one year ago
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    yes

  20. mckenzieandjesus
    • one year ago
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    Thank You!. I never understood those but now I do. A lot simpler than I thought.

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