Critical numbers help? I will reward with a medal!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Critical numbers help? I will reward with a medal!

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\sin^2x+cosx\] \[0
Get that derivative? :U
sinx (2cosx -1)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Mmm ok looks good! :)
\[\large\rm \sin x (2\cos x -1)=0\]Apply your Zero-Factor Property\[\large\rm \sin x=0\qquad\qquad\qquad 2\cos x-1=0\]
sine is zero at what angles?
I'm not sure how to get that answer.
Don't remember your trig..? :(
I was horrible at memorizing trig stuff. I enjoyed solving certain types of problems with them, but quite frankly I don't remember much of anything except for a few identities.
Is it a particular formula, or is it just something you'd have to memorize?
Ugh OpenStudy freezing on me again.....
It does that to me a lot.
(this may seem like a stupid question, but which part is sine?
|dw:1444434263248:dw|
|dw:1444434276482:dw|sine is the y-coordinates
So we want to know which angles give us a y-coordinate of 0
So the 180 angle
Hmm there's another one :d
Oops! Didn't see that. The 0 angle
Oh wait... was your interval really given like this? \(\large\rm 0
That's what it looked like.
Oh ok :) Then I guess we can throw out the 0, since it's not in our interval. So then, \(\large\rm \sin x=0\) implies that our angle \(\large\rm x=\pi\). Ok great, we've found one critical point.
\[\large\rm 2\cos x-1=0\]Solving for cos x,\[\large\rm \cos x=\frac{1}{2}\]
|dw:1444434611166:dw|Cosine is your x-coordinates
So 60 degrees for cosine?
|dw:1444434707066:dw|
I'm not sure why I keep looking only in the first section. Thank you again for pointing that out.
60 and 300
Degrees are icky :) lol You gotta try to get comfortable with radians XD
Ok great so we've found all of our critical points!! \[\large\rm x=\frac{\pi}{3},~\pi,~\frac{5\pi}{3}\]
Here is the graph in case you wanted to see it, it's pretty cool https://www.desmos.com/calculator/6sbfzaocym You can clearly see a hill top at pi/3 and 5pi/3 and the bottom of a valley at the pi.
Wow! I never knew you could graph something like this on desmos. That's very interesting.
My connection on this site is horrible. sorry
Thank you for your help! (I'll probably be back on here soon with more questions)
Yah it's a little complicated to graph just a small interval on desmos, you have to put it into set brackets { } and the interval comes first, then colon, then your function.
Could you help me with one last thing really quickly?
sure
I know the derivative is sinx (2cosx -1) but I can't exactly figure out how to get that.
oh you cheated on the first part? come on broski -_-
No, I didn't cheat.
The assignment gives me the derivative
Oh :O
\[\large\rm y=(\sin x)^2+\cos x\]\[\large\rm y'=2(\sin x)(\sin x)'+(\cos x)'\]Start by applying power rule to the sine function. Then we have chain rule as well.
You really have to remember your sine and cosine derivatives to get through this one :)
\[\large\rm y'=2(\sin x)(\cos x)+(-\sin x)\]
And then factor a sin x out of each term.
Oh okay! I see now. Thank you. :)
:D

Not the answer you are looking for?

Search for more explanations.

Ask your own question