At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Mmm ok looks good! :)

sine is zero at what angles?

I'm not sure how to get that answer.

Don't remember your trig..? :(

Is it a particular formula, or is it just something you'd have to memorize?

Ugh OpenStudy freezing on me again.....

It does that to me a lot.

(this may seem like a stupid question, but which part is sine?

|dw:1444434263248:dw|

|dw:1444434276482:dw|sine is the y-coordinates

So we want to know which angles give us a y-coordinate of 0

So the 180 angle

Hmm there's another one :d

Oops! Didn't see that. The 0 angle

Oh wait... was your interval really given like this?
\(\large\rm 0

That's what it looked like.

\[\large\rm 2\cos x-1=0\]Solving for cos x,\[\large\rm \cos x=\frac{1}{2}\]

|dw:1444434611166:dw|Cosine is your x-coordinates

So 60 degrees for cosine?

|dw:1444434707066:dw|

I'm not sure why I keep looking only in the first section. Thank you again for pointing that out.

60 and 300

Degrees are icky :) lol
You gotta try to get comfortable with radians XD

Wow! I never knew you could graph something like this on desmos. That's very interesting.

My connection on this site is horrible. sorry

Thank you for your help! (I'll probably be back on here soon with more questions)

Could you help me with one last thing really quickly?

sure

I know the derivative is sinx (2cosx -1)
but I can't exactly figure out how to get that.

oh you cheated on the first part? come on broski -_-

No, I didn't cheat.

The assignment gives me the derivative

Oh :O

You really have to remember your sine and cosine derivatives to get through this one :)

\[\large\rm y'=2(\sin x)(\cos x)+(-\sin x)\]

And then factor a sin x out of each term.

Oh okay! I see now. Thank you. :)

:D