anonymous
  • anonymous
A single card is chosen at random from a shuffled standard fifty-two card deck (no jokers). Find the following probabilities. 1)What is the probability that the card is black? 2)What is the probability that the card is a heart? 3)What is the probability that the card is either a diamond or a 4? 4)What is the probability that the card is at least a 7 and at most a 9? That is, P(≥7∩≤9)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I guess 1) 1/2 2) 1/4 3) 17/52 or 16/52 i don't know for sure 4)21/52
amistre64
  • amistre64
if we out all the diamonds and 4s into a pile, how many cards would be in the pile?
amistre64
  • amistre64
if w put all the 7s, 8s and 9s in a pile, how many would be in the pile?

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amistre64
  • amistre64
21 might be a typo ... 12/52 seems better for that one
anonymous
  • anonymous
k
anonymous
  • anonymous
im a bit confuse 12/52 is from which question?
amistre64
  • amistre64
the one that has 21 in it ...
anonymous
  • anonymous
question 4) ?
anonymous
  • anonymous
\[P \left( A \cup B \right)=P \left( A \right)+P \left( B \right)\]-P(A intersection B)
anonymous
  • anonymous
all are correct except for 4 ?
amistre64
  • amistre64
if we put all the diamonds and 4s into a pile, how many cards would be in the pile?
anonymous
  • anonymous
there are 13 diamond and 4 (club diamond, heart and spade)
amistre64
  • amistre64
13 diamonds, plus 1 card from each of the other 3 suits 13+3
anonymous
  • anonymous
16/52
amistre64
  • amistre64
yes
anonymous
  • anonymous
ok
amistre64
  • amistre64
if we take a 7, 8, and 9 from each suit ... so 3 cards out of 4 suits would be how many cards?
anonymous
  • anonymous
12 ?
amistre64
  • amistre64
yes, so 12/52 for that last one .. not 21/52
anonymous
  • anonymous
ok i see
anonymous
  • anonymous
now we are done here ?
amistre64
  • amistre64
the rest are fine, so yeah
anonymous
  • anonymous
thank you so much for the help
amistre64
  • amistre64
good luck :)

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