anonymous
  • anonymous
Two six sided dice (one is red, one is green) are rolled. Determined the following probabilities: 1) What is the probability that the red die is even and the green die is odd? That is, P(R=even∩G=odd) 2)What is the probability that the sum of the red and green values is 8 . 3) What is the probability that the sum of the red and green values is <7 ? That is, P(R+G<7). 4) What is the probability that red value is ≤ green value? That is, P(R≤G) 5) What is the probability that red value ≤ green and the green value is <6 ? That is, P(R≤G∩G<6)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 is .25 do you know why?
anonymous
  • anonymous
2 is 1/36
anonymous
  • anonymous
no

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anonymous
  • anonymous
no sorry 7/36
anonymous
  • anonymous
ok for number 1 do you know that if you have two independent probabilities you multiply them to find their combined probability?
anonymous
  • anonymous
so the P(even dice roll)=.5 and P(odd dice roll)=.5 so .5•.5=.25
anonymous
  • anonymous
there like 2 dice(6*6=36)
anonymous
  • anonymous
i see, so is 1/4
anonymous
  • anonymous
\[\frac{ 3 }{ 6 } \times \frac{ 3 }{ 6 }=?\]
anonymous
  • anonymous
yea
anonymous
  • anonymous
that solve the first part, is 1/4
anonymous
  • anonymous
yea but i would use decimals unless it asks for fractions
anonymous
  • anonymous
k
anonymous
  • anonymous
ok so #2
anonymous
  • anonymous
there are 36 total combinations and only 7 add up to 8
anonymous
  • anonymous
so 7/36 would be the probability
anonymous
  • anonymous
k
anonymous
  • anonymous
sorry wait i didnt account for 1 so its 8/36 which can be simplified
anonymous
  • anonymous
1,7 2,6 3,5 4,4 4,4 5,3 6,2 1,7
anonymous
  • anonymous
those are the combos that add up to 8 for the red and green
anonymous
  • anonymous
16/36?
anonymous
  • anonymous
well no because there are 16 numbers but they come in pairs
anonymous
  • anonymous
so?
anonymous
  • anonymous
ya u are right
anonymous
  • anonymous
{1,7} , so on
anonymous
  • anonymous
yea
anonymous
  • anonymous
ok so #2 is?
anonymous
  • anonymous
2. 26,35,44,53,62 P=5/36
anonymous
  • anonymous
^^^^^
anonymous
  • anonymous
but its 6 not 5 because th 4,4 repeats
anonymous
  • anonymous
that solve second question
anonymous
  • anonymous
yea
anonymous
  • anonymous
correct.6/36
anonymous
  • anonymous
so #3 do you know what to do??
anonymous
  • anonymous
finding a numbers that is less that 7
anonymous
  • anonymous
yea but combos like {1,5} so on
anonymous
  • anonymous
but not =7 its <7
anonymous
  • anonymous
ya i notice that
anonymous
  • anonymous
12/36
anonymous
  • anonymous
try again
anonymous
  • anonymous
11,12,13,14,15,21,22,23,24,31,32,33,41,42,51first is G,second is Red same is first Red,second is Green P=30/36=5/6
anonymous
  • anonymous
try to make a diagram or draw it
anonymous
  • anonymous
already did
anonymous
  • anonymous
i miss some numbers
anonymous
  • anonymous
|dw:1444443620290:dw|
anonymous
  • anonymous
so count all the numbers under the red and thats the combo totals
anonymous
  • anonymous
so there is 15 total
anonymous
  • anonymous
indeed already saw the answer from @surjithayer
anonymous
  • anonymous
not 30
anonymous
  • anonymous
well actualy no thats right it repeats
anonymous
  • anonymous
so yea 30/36
anonymous
  • anonymous
now part 4
anonymous
  • anonymous
same thing just draw it out
anonymous
  • anonymous
is 30/36 ?
anonymous
  • anonymous
12/36 or
anonymous
  • anonymous
4) is 7/6 5) 7/36
anonymous
  • anonymous
sorry is 10/36 for the last part
zepdrix
  • zepdrix
I don't quite understand your fraction for part 4. 7/6? So you're saying the red die will be less than the green die over 100% of the time?
anonymous
  • anonymous
i just simplify the number 16/36
zepdrix
  • zepdrix
Which does not simplify to 7/6... but anyway I think maybe you missed a few, hmm If a 1 is rolled on the red die, and we want the green to be greater than or equal to that, We can roll any number on the green die, ya? If a 2 is rolled on the red die, We can roll any number larger than a 1 on the green die. R1 G123456 R2 G 23456 R3 G 3456 R4 G 456 R5 G 56 R6 G 6 =6+5+4+3+2+1 I think that's 21 of the 36 combinations, isn't it? :o
anonymous
  • anonymous
ya is 21/36 i guess i miss some calculation

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