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anonymous

  • one year ago

Where does the graph of this function cross the x-axis? f(x)=x^2+14x+24/3x^2-11

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    The function is this right? \[\Large f(x) = \frac{x^2+14x+24}{3x^2-11}\]

  3. anonymous
    • one year ago
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    yes

  4. jim_thompson5910
    • one year ago
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    First replace f(x) with 0. Then multiply both sides by \(\Large 3x^2-11\) \[\Large f(x) = \frac{x^2+14x+24}{3x^2-11}\] \[\Large 0 = \frac{x^2+14x+24}{3x^2-11}\] \[\Large 0*(3x^2-11) = \frac{x^2+14x+24}{3x^2-11}*(3x^2-11)\] \[\Large 0 = x^2+14x+24\] \[\Large x^2+14x+24=0\] Do you see how to solve from here?

  5. anonymous
    • one year ago
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    Got it! (x+2)(x+12) right?

  6. jim_thompson5910
    • one year ago
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    very good

  7. jim_thompson5910
    • one year ago
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    so if (x+2)(x+12) = 0 then either x+2 = 0 or x+12 = 0 solve each equation for x to get your 2 answers

  8. anonymous
    • one year ago
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    x=-2 and x=-12?

  9. jim_thompson5910
    • one year ago
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    both are correct

  10. anonymous
    • one year ago
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    All right, thank you so much!!

  11. jim_thompson5910
    • one year ago
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    you're welcome

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