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anonymous

  • one year ago

Which of the following statements is true? The volume of the solid formed by rotating the region bounded by the graph of y = x2, x = 3, y = 0 around the x-axis is https://gyazo.com/d4c15f518e12e0ca068dbf232b0c7b69

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  1. jim_thompson5910
    • one year ago
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    do you have the graph set up?

  2. anonymous
    • one year ago
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    |dw:1444444321553:dw|

  3. jim_thompson5910
    • one year ago
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    this is what your graph should look like

  4. anonymous
    • one year ago
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    Oops, sorry Just a bit tired.

  5. jim_thompson5910
    • one year ago
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    the region in blue is going to be revolved around the x axis

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  6. anonymous
    • one year ago
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    By looking at the graph, I'm going to have to say it's B

  7. jim_thompson5910
    • one year ago
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    |dw:1444446589968:dw|

  8. jim_thompson5910
    • one year ago
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    |dw:1444446606361:dw|

  9. anonymous
    • one year ago
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    If I'm following you correctly, 9.

  10. jim_thompson5910
    • one year ago
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    the vertical distance from the curve to the x axis

  11. jim_thompson5910
    • one year ago
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    it's going to be something with x in it

  12. anonymous
    • one year ago
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    Nope, completely lost here. |dw:1444446815097:dw| You're asking for that right?

  13. jim_thompson5910
    • one year ago
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    yes that length in terms of x (imagine it sliding back and forth between x = 0 and x = 3)

  14. anonymous
    • one year ago
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    Well it would change depending on what x is in the function y=x^2

  15. jim_thompson5910
    • one year ago
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    it's simply x^2, right?

  16. jim_thompson5910
    • one year ago
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    whatever x is, the vertical distance from the curve to the x axis is x^2 units

  17. anonymous
    • one year ago
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    jim pls why would you ask for the obvious? I am very tired ;(

  18. anonymous
    • one year ago
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    ok

  19. anonymous
    • one year ago
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    So how would I used that?

  20. jim_thompson5910
    • one year ago
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    |dw:1444447162670:dw|

  21. jim_thompson5910
    • one year ago
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    this 3D figure is made up of disks that look like this |dw:1444447207593:dw|

  22. jim_thompson5910
    • one year ago
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    imagine cutting it up into infinitely many disks that are infinitesimally small then glue those pieces together to form this 3D shape this is effectively what you are doing when you evaluate \[\Large \pi\int_{a}^{b}(R)^2dx\] \[\Large \pi\int_{0}^{3}(x^2)^2dx\] \[\Large \pi\int_{0}^{3}(x^4)dx\]

  23. anonymous
    • one year ago
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    nope, did not get it

  24. anonymous
    • one year ago
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    I'll look over it tomorrow when I'll be well rested.

  25. jim_thompson5910
    • one year ago
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    hmm strange how the system says it's wrong

  26. jim_thompson5910
    • one year ago
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    could be a typo somewhere

  27. anonymous
    • one year ago
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    What system?

  28. jim_thompson5910
    • one year ago
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    aren't you saying it's wrong?

  29. jim_thompson5910
    • one year ago
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    or the computer is telling you it's wrong?

  30. anonymous
    • one year ago
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    I was saying, I did not personally understand it very well.

  31. jim_thompson5910
    • one year ago
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    oh ok

  32. anonymous
    • one year ago
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    You are right. ;)

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