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anonymous

  • one year ago

3) How long does it take the apple to reach your friend? (**HINT: The time would be the x-coordinate of the highest point.) Double click on the space below to show your work. h(t) = – 16t2 + 38.4t + 0.96 H= Height. T= Time (seconds). I WILL FAN AND MEDAL FOR ANSWERS AND WORK.

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  1. anonymous
    • one year ago
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    Set the equation = 0. Then use quadratic formula.

  2. anonymous
    • one year ago
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    It is supposed to be h(t) = -16t^2 + 38.4t + 0.96

  3. anonymous
    • one year ago
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    Ok! Set the equation = 0.

  4. anonymous
    • one year ago
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    \(\huge -16t^2+38.4t+0.96=0\)

  5. anonymous
    • one year ago
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    Do you know the quadratic formula?

  6. anonymous
    • one year ago
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    Then it would be \[-38\pm \sqrt{38.4^{2}-4(-16)(0.96)} / 2(-16)\]

  7. anonymous
    • one year ago
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    Right?

  8. anonymous
    • one year ago
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    @mathway

  9. anonymous
    • one year ago
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    The beginning is supposed to be -38.4 not just -38.

  10. anonymous
    • one year ago
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    Yes! Now solve for t. :) And since it is time, your answer shouldn't be the negative one.

  11. anonymous
    • one year ago
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    Let me know if you got an answer, so I may check if it's right. :)

  12. anonymous
    • one year ago
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    So then I get: \[-38.4\pm \sqrt{1,536} / -32\] I'm confused on what to do after this step.

  13. anonymous
    • one year ago
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    \(\huge \frac{-38.4±\sqrt {1536}}{-32}\) Frind the square root of 1536 first.

  14. anonymous
    • one year ago
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    \[16\sqrt{6}\]

  15. anonymous
    • one year ago
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    \(\huge \frac{-38.4±16\sqrt {6}}{-32}\rightarrow\) \(\huge \frac{-38.4+16\sqrt {6}}{-32} \) & \(\huge \frac{-38.4-16\sqrt {6}}{-32} \)

  16. anonymous
    • one year ago
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    Should it be in radical form or could it be in decimal form?

  17. anonymous
    • one year ago
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    So how do we get the answer from there? It should be in decimal form since we are trying to find how many seconds it takes the apple to reach your friend.

  18. anonymous
    • one year ago
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    Great! Now get a calculator and solve for it. Notice that \(\sqrt{6} =2.45\).

  19. anonymous
    • one year ago
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    \(\huge \frac{-38.4+16(2.45)}{-32}\) &\(\huge \frac{-38.4-16(2.45)}{-32}\)

  20. anonymous
    • one year ago
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    Still confusing?

  21. anonymous
    • one year ago
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    I got -0.02

  22. anonymous
    • one year ago
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    Or should it be positive 0.02? @mathway

  23. anonymous
    • one year ago
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    You're supposed to get \(\huge \color{red}{ \text{TWO}}\) solutions. and \(-0.02\) is one. And since it is negative, it can't be the time. So solve for the other one.

  24. anonymous
    • one year ago
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    2.4 seconds rounded.

  25. anonymous
    • one year ago
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    Correct! :)

  26. anonymous
    • one year ago
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    Thank you so much!!!

  27. anonymous
    • one year ago
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    No problem! :)

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