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Set the equation = 0. Then use quadratic formula.

It is supposed to be h(t) = -16t^2 + 38.4t + 0.96

Ok! Set the equation = 0.

\(\huge -16t^2+38.4t+0.96=0\)

Do you know the quadratic formula?

Then it would be \[-38\pm \sqrt{38.4^{2}-4(-16)(0.96)} / 2(-16)\]

Right?

The beginning is supposed to be -38.4 not just -38.

Yes! Now solve for t. :) And since it is time, your answer shouldn't be the negative one.

Let me know if you got an answer, so I may check if it's right. :)

So then I get: \[-38.4\pm \sqrt{1,536} / -32\] I'm confused on what to do after this step.

\(\huge \frac{-38.4±\sqrt {1536}}{-32}\)
Frind the square root of 1536 first.

\[16\sqrt{6}\]

Should it be in radical form or could it be in decimal form?

Great! Now get a calculator and solve for it. Notice that \(\sqrt{6} =2.45\).

\(\huge \frac{-38.4+16(2.45)}{-32}\) &\(\huge \frac{-38.4-16(2.45)}{-32}\)

Still confusing?

I got -0.02

2.4 seconds rounded.

Correct! :)

Thank you so much!!!

No problem! :)