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anonymous
 one year ago
4) What is the height of the apple when your friend catches it?
(**HINT: The height would be the ycoordinate of the highest point.)
Double click on the space below to show your work.
h(t) = 16t^2 + 38.4t + 0.96
h= height t= time (seconds)
I will fan and medal for work plus answers!
anonymous
 one year ago
4) What is the height of the apple when your friend catches it? (**HINT: The height would be the ycoordinate of the highest point.) Double click on the space below to show your work. h(t) = 16t^2 + 38.4t + 0.96 h= height t= time (seconds) I will fan and medal for work plus answers!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I find the height? How do I switch the equation to find the height instead of the time? I can solve it just not sure how to set it up.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is more to this question right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The information is enough. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0naw dude its asking for the vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would I just substitute the time that we just figured out into the equation? The 2.4 seconds?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444445933109:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No you don't have to. Just make t=0. :) \(h(t) = 16(0)2 + 38.4(0) + 0.96\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why would you do that?? is the friend .96 ft off the ground

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The height we're finding is the same thing as the vertex. =_= Notice that the vertex in this case is the maximum because \(a\) is a negative.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0t=o is your initial starting point not the vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If (0,y) < this is the vertex. Please stop misguiding the one who asked.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you solve the equation mathway gave me, I got 0.96.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0b/2a is the x coordinate and f(b/2a) is your Y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"(**HINT: The height would be the ycoordinate of the highest point.)" Which means that you need to find the ycoordinate.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, it is \(\huge 0.96\). :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0MAX HIGHT WHICH IS THE Y OF YOUR VERTEX

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is 0 time e=meaning the apple hasnt been thrown yet...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is not a vertex because it is PART OF THE VERTEX. It is the xintercept.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how can your friend catch something that hasnt been thrown?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha Please confirm this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no x intercept is finding the root dude...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The question I posted before this was asking if a person threw an apple how many seconds would it take to reach the other person 3 stories up? We solved and got 2.4 seconds.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Show me how you will find the height then. You keep on complaining, but you're not showing any work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Of course it is correct. I was the one who helped her. :P

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0`(**HINT: The height would be the ycoordinate of the highest point.)`

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but now plug that number into the function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathway im not calling you dumb people make mistakes and this is one of yours

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You would still get the same answer either way, 0.96.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes buy he cant say thats what it is you have to explain it in the context of the problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since its a root ofcourse it would cancle out the other 2 but in a 4th power polynomial that would fail miserably

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the fundamental way to explain the answer is V = {(b/2a),f(b/2a)} and you look for Y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay guys last question! Using the same equation  h(t) = 16t^2 + 38.4t + 0.96 With h = height and t = time in seconds 5) Suppose your friend does not catch the apple and it falls back to the ground. How long did it take the apple to hit the ground? (**HINT: When the apple hits the ground is when the graph hits the xaxis.)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444446732488:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0calm plz use the hint highest point = max so we need y coordinate of the max point (max=vertex)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0lol sorry for late reply >.< internet iz very slow .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok hold up go back what did you get for your sec for the apple to get to him??????!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the kid on the 3rd floor????

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0x coordinate of the vertex can be any number (0,y) = yintercept :=)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 38.4 \pm \sqrt{38.4^{2}4(16)(0.96)} }{ 2(16) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea lol but only if it is centered on the orgin would that be a vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea @tbull1221 that works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what does that give you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 38.4 \pm \sqrt{1536} }{ 32 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then you get: \[\frac{ 38.4 \pm 16\sqrt{6} }{ 32 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"x coordinate of the vertex can be any number (0,y) = yintercept :=)" @Nnesha Thank you for backing up! At least I know that I'm not dumb and I don't necessarily have to say irrelevant things when I made a mistake. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw dude the other answer for the seconds it takes was wrong its 4.8sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0plz read http://hotmath.com/hotmath_help/topics/vertexofaparabola.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im in 3rd year calc and 2 year stat i know how to find the vertex of a parabola...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can someone please just give me an answer for #5? My computer is about to die. I will fan and medal if i haven't already.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I highly suggest that you don't call me "dude." We are not close.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And is the seconds answer 2.4 or 4.8?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry im a fairly welcoming person i dont show nor mean it in any form of disrespect

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the one that said "the amount of seconds for the apple to reach the friend" is 4.8 sec

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0people make mistakes i do all the time everyday more than 100 times it's okay we can correct it nicely :=) so please :=)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so that is your seconds or X on your vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then plug that into your equation and you will get the amount of feet it took for the friend to get the apple

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then for this what you did was fine you just plug the numbers into the quadratic equation and you will get the time it took to hit the ground

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you understand why you were wrong @mathway ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not trying to disrespect you. at this point im trying to help you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0go up like 5 comments and i did a stepbystep of the process

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the seconds is 4.8? And What is the answer to #5?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05) Suppose your friend does not catch the apple and it falls back to the ground. How long did it take the apple to hit the ground? (**HINT: When the apple hits the ground is when the graph hits the xaxis.)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but both of the ones before that were wrong because the sec were wrong so the FT to make to him wouldnt be .96

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so with the answer to b/2a plug that number into the equation given and you will get the distance of the throw to the vertex (the friend)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because mathway said it was 2.4 sec but it wasnt it was 4.8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then plug in 4.8 into the equation to get the answer to the Max height

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then what you did with the quadratic equation would give you #5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@tbull1221 are you still there??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0aww tbull got off :(

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0\[\begin{align} h(t) = 16t^2 + 38.4t + 0.96 &\implies h(t) = 16t^2+\frac{192}{5}t+\frac{24}{25} \\&\implies h(t) =t^2 \frac{12}{5}t \frac{3}{50} =0 \\&\implies h(t) = \left(t^2\frac{12}{5}t \right) =\frac{3}{50} \\&\implies h(t) = \left(t^2 \frac{12}{5}t +\frac{36}{25} \right)=\frac{3}{50}+\frac{36}{25} \\ &\implies h(t) = \left(t\frac{6}{5}\right)^2=\frac{3}{2} \\&\implies h(t) : ~t=\frac{6}{5}\pm\sqrt{\frac{3}{2}} \end{align}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0time is always positive in this case, therefore \(t= \frac{6}{5} +\sqrt{\frac{3}{2}}\)
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