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anonymous
 one year ago
Simplify the rational expression. State any restrictions on the variable.
anonymous
 one year ago
Simplify the rational expression. State any restrictions on the variable.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha do you know anything about this?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what two numbers multiply to 24 and add to 10?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.112+2 = 14 not 10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444458852967:dw I believe this is the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0opps for some reason I thought i read multiply lol thats what I get for 15 hours of school work today

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.16 and 4 fit the description, no? 6 + (4) = 10 6 times 4 = 24

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes that is correct. I see what you mean by that now

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so that means n^4  10n^2 + 24 factors to (n^2  6)(n^2  4) we can then further factor n^2  4 down into (n2)(n+2)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so overall, n^4  10n^2 + 24 completely factors to (n^2  6)(n2)(n+2)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you'll do the same for the denominator and see if you can cancel anything

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so the bottom line reads n^49n^2+18 Im confused:/ Would I need to find a number that multiplies to 24 and adds to 9?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1multiplies to 18 actually

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1find two numbers that multiply to 18 and add to 9

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 6 and 3 right cause 6*3=18 and 6+3=9

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I think that's what you meant to say?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so n^49n^2+18 factors to (n^26)(n^23)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1n^4  10n^2 + 24 completely factors to (n^2  6)(n2)(n+2) n^49n^2+18 completely factors to (n^26)(n^23)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1at this point, I see a pair of terms cancelling

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so (n^22) (n+2) (n^23) (n^24) (n^23)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I think you meant to say `(n2) (n+2)` in your first step

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1but yeah the final answer is \[\Large \frac{n^24}{n^23}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what would the restrictions be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would the answer be this dw:1444460035990:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could we work the problem out further? I quess i still dont 100% understand

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the denominator factors into (n^26)(n^23) each piece is set equal to 0 and solved for to get n^26 = 0 n^2 = 6 n = sqrt(6) or n = sqrt(6) n^23 = 0 n^2 = 3 n = sqrt(3) or n = sqrt(3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be the square root of those numbers ( 6, 3)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so the restrictions are actually \[\Large n \ne \pm \sqrt{6}\] \[\Large n \ne \pm \sqrt{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444460209535:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much!! You are a lifesaver and such a great teacher! My husband usually helps me with math but he doesn't know this type of stuff! Im giving you a medal for your help.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'm glad it's making more sense now
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