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anonymous
 one year ago
Medal & fan
Using a directrix of y = 2 and a focus of (1, 6), what quadratic function is created?
anonymous
 one year ago
Medal & fan Using a directrix of y = 2 and a focus of (1, 6), what quadratic function is created?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha @zepdrix @MeganEdward

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or @dan815 or @merchandize lol

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444448203481:dw ;;

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Recall that the vertex of a parabola lies halfway between the focus and the directrix

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright let's pick point (x,y) dw:1444448374229:dw we need to find distance between the point (x,y) and focus and the distance between point and directirx \[\sqrt{(x  a)^2+(y b)^2}= \left yc \right\] \[\sqrt{(x 1)^2 + (y6)^2} = (y(2))^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2npI yc I is same as (yc)^2 and (a,b) is the focus point any question ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I'm just completely lost :/ Don't understand this question as well as the other one.. I dont remember what a directrix even is

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i see sorry directrix is a line y = c dw:1444448897371:dw and the focus point is at (1,6)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ahh distance between the point `on parabola ` i missd that part :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, I just dont get it :(

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2y = c ( it's horizontal line ) so y =2 draw a horizontal line at 2 dw:1444449356899:dw red line is directrix right

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2now draw focus point (1,6) dw:1444449417779:dw read the definition on the dan's secreenshot :P dw:1444449585947:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I get everything up to this point

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2to write an equation we have to find 1) distance between the point `on parabola ` to the focus 2nd) distance between the point " on parabola" to the directrix

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay is there a formula for this?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444449758151:dw blue line distance ( between point and directrix ) red one distance between (point and focus ) and the equation i posted above \[\huge\rm \sqrt{(xa)^2 +(yb)^2 }= \left yc \right\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2(a,b) is the focus point c= directrix

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2now plugin the numbers (a,b) = (1,6) c= 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so sqrt of (x  1)^2 + (y  6)^2 = (y + 2)^2 right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2hmm \[\huge\rm \sqrt{(x1)^2 +(y6)^2 }= \left y+2 \right\] take square both sides please let me know if you don't get anything i'm sleepy e,e

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ill let you know, thanks for helping! And what do you mean by "take square both sides" ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2when we take square both sides tit would be \[\huge\rm (x1)^2 +(x6)^2 = (y+2)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okay, right. to get rid of the sqrt and the absolutes

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2and then foil (x6)^2 is same as (x6)(x6) same with (y+2)^2 bec as dan mentioned we need an equation y= form

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ugh typo it's \[\huge\rm (x1)^2 +(y6)^2 = (y+2)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i foil x1 ^2 too?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2sorry sorry :( (y6)(y6)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well i'll saw leave it as (xh)^2 we can write an equation in vertex form \[y=a(xh)^2+k\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so (y^2  12y + 36) + (x1)^2 = y^2 +4y + 4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2right now combine like terms dw:1444450916236:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2sorry about the cool writing ,,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, that last thing threw me off

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ohh okay which one please ask :=)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i just moved all terms to the right side except (x1)^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh never mind, i get it! Sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay and now what do i do?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2let me think ... :( i'm lost :( wait a sec plz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just submitted the exam because i have to go to bed. I got the answer wrong too :/ but thanks for all your help!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright i'll going to expand (x1)^2 \[\large\rm x^22x+1 +y^212y+36=y^2+4y+4\] dw:1444451678408:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i shouldn't start helping u so my fault i apologize i'll look at it tomorrow will try to explain and i wil lfocus on this
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