## anonymous one year ago Find the average value of f(x) = sin(x) over the interval [0, π].

1. anonymous
2. anonymous

@jim_thompson5910

3. jim_thompson5910

M = average value of f(x) from x = a to x = b $\Large M = \frac{1}{b-a}\int_{a}^{b}f(x)dx$

4. jim_thompson5910

In this case, a = 0 b = pi f(x) = sin(x) $\Large M = \frac{1}{b-a}\int_{a}^{b}f(x)dx$ $\Large M = \frac{1}{\pi-0}\int_{0}^{\pi}\sin(x)dx$ $\Large M = ??$

5. anonymous

That's basically what I did without multiplying by 1/pi

6. anonymous

So it should be 2/pi

7. jim_thompson5910

you are correct