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anonymous

  • one year ago

If a spring is oscillating (moving) according to the velocity equation v(t) = sin(t) (in ft/s), then what is its displacement over its first π seconds of travel?

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  1. anonymous
    • one year ago
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    https://gyazo.com/81f7b024f75d96645c93c5a77057d0cd

  2. anonymous
    • one year ago
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    @jim_thompson5910

  3. anonymous
    • one year ago
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    All I did was plug in pi, which seems extremely wrong.

  4. anonymous
    • one year ago
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    Maybe plug pi into the integral?

  5. jim_thompson5910
    • one year ago
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    the displacement is equal to the area under the velocity curve

  6. jim_thompson5910
    • one year ago
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    so you just need to evaluate \[\Large \int_{0}^{\pi}\sin(t)dt\]

  7. anonymous
    • one year ago
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    Final answer is 2?

  8. jim_thompson5910
    • one year ago
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    yeah

  9. dan815
    • one year ago
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    displacement = velocity * time

  10. dan815
    • one year ago
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    |dw:1444449711933:dw|

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