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@Empty Hey there! are you available? :)
Heyo, alright so any ideas on how to make this continuous?
Setting two of the equations to equal each other and then subbing a and b in
Yeah you're on the right track, what we need to do to make the function continuous is have their heights match up at the same value of x. In order to do that, we take the first equation and set it equal to the second equation and plug in x=2 since at that point they need the same height. Similarly you will make the second and third equal and plug in the x value there to make them equal. Then you have two equations and two unknowns to solve for, the values of a and b that make your function continuous!
Yay!! So part a after plugging 2 in where x is: 4=4a-2b+3?
The first two simplify to: 1=4a-2b
Second two simplify to: 5a=3b+5
when you plug in 3, 9 a - 3b + 3 = 12 -a + b 10a -4b = 9 how did you get 5a=3b+5 for second two ? 4a -2b = 1 is correct :)
Ah sorry, I accidentally plugged 2 instead of 3 on the last two =.=
thought so...since f(x) to be continuous at x =3, f(3)- and f(3)+ should be equal.
Ahh, gotcha. So now I solve them for a and b?
a = 13/20 ? o.o
I don't know how I am getting these weird numbers :/
how did you solve them ? because i get a different answer...
multiply equation 1 by 2 8a -4b =2 subtract this from equation 2 10a - 4b = 9 - 8a -4b = 2 ================= 2a + 0 = 7 a =7/2
Oh. then b = 13/2
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Lol. Thaaank you. Sorry about my brain deadness.
no problem, welcome ^_^