Math2400
  • Math2400
can someone please help me out this ><
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Math2400
  • Math2400
amistre64
  • amistre64
Coef means: coefficient. the coef for the constant term (the y intercept) is given the coef for the variable term (the slope) is given
amistre64
  • amistre64
hmm, it appears that they already GIVE you the regression equation where it says: "The regression equation is"

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Math2400
  • Math2400
@ganeshie8 if u get a second lmk if u could help me out with this one ><
Math2400
  • Math2400
would it be: 0.92 + 2.06x ?
Vocaloid
  • Vocaloid
almost, it says to round to 3 decimal places
Vocaloid
  • Vocaloid
you picked the right numbers, you just need to round differently
Math2400
  • Math2400
so like 0.920 + 2.060x ?
Vocaloid
  • Vocaloid
look at the table again
Vocaloid
  • Vocaloid
the constant is 0.919 and the coefficient is 2.0647, which rounds to 2.065
Math2400
  • Math2400
ok and then for the next question do i just plug in 25 C to get 52.42 or do I use the graph?
Math2400
  • Math2400
*table
Vocaloid
  • Vocaloid
use the function, let x = 25
Math2400
  • Math2400
so 52.544 ?
Math2400
  • Math2400
thank you so much @Vocaloid you're the only one who has been able to help me on this one lol. it goes on to ask: the percent of the variation in beak heat loss is explained by the straight-line relationship with temperature is ______. Round your answer to one decimal place. so it would it be 83.6% ?
Vocaloid
  • Vocaloid
yup!
Math2400
  • Math2400
awesome and then the last one says: Using the information in Figure 4.9, the correlation r between beak heat loss and temperature is ______. Round your answer to 3 decimal places. Is it 4.507??
Vocaloid
  • Vocaloid
nope they give you r^2, just take the square root of that to find r
Math2400
  • Math2400
wait which is r^2?
Math2400
  • Math2400
@Vocaloid
Vocaloid
  • Vocaloid
R-Sq
Math2400
  • Math2400
so change it to 0.824 and square root to get 0.908 ?
Vocaloid
  • Vocaloid
yes
Math2400
  • Math2400
Thank you so much :)

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