anonymous
  • anonymous
Simple derivative question.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
I assume you implicitly differentiate and substitute in x=0 ? You'll just have an equation in terms of y then? Or am I doing something wrong?
zepdrix
  • zepdrix
Yah that's strange, seems like they would want you to evaluate this at some particular y'(x,y) since it's going to depend on both variables :d weird

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zepdrix
  • zepdrix
But ya that sounds right, implicit, then 0 all your x's, and simplify Getting stuck on differentiating any of the pieces? :o
anonymous
  • anonymous
No I can differentiate it find. Just stuck on the actual understanding of the question.
anonymous
  • anonymous
Possible to get the y value maybe?
zepdrix
  • zepdrix
Oh oh yes, it looks like we can get the y-coordinate that corresponds to x=0 from the original expression!
zepdrix
  • zepdrix
I think so at least, it looks like a lot of stuff is going to cancel out.
anonymous
  • anonymous
Really? Well we then get ln(y)+y=y/2 right?
zepdrix
  • zepdrix
y/1 on the right side
anonymous
  • anonymous
oooooooooooo. The y's cancel.
zepdrix
  • zepdrix
ooo they so sneaky :D
anonymous
  • anonymous
oooooooooooo. The y's cancel.
anonymous
  • anonymous
Wow that's clever :P .
anonymous
  • anonymous
Thanks!
zepdrix
  • zepdrix
\c:/

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