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anonymous

  • one year ago

Simple derivative question.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I assume you implicitly differentiate and substitute in x=0 ? You'll just have an equation in terms of y then? Or am I doing something wrong?

  3. zepdrix
    • one year ago
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    Yah that's strange, seems like they would want you to evaluate this at some particular y'(x,y) since it's going to depend on both variables :d weird

  4. zepdrix
    • one year ago
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    But ya that sounds right, implicit, then 0 all your x's, and simplify Getting stuck on differentiating any of the pieces? :o

  5. anonymous
    • one year ago
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    No I can differentiate it find. Just stuck on the actual understanding of the question.

  6. anonymous
    • one year ago
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    Possible to get the y value maybe?

  7. zepdrix
    • one year ago
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    Oh oh yes, it looks like we can get the y-coordinate that corresponds to x=0 from the original expression!

  8. zepdrix
    • one year ago
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    I think so at least, it looks like a lot of stuff is going to cancel out.

  9. anonymous
    • one year ago
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    Really? Well we then get ln(y)+y=y/2 right?

  10. zepdrix
    • one year ago
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    y/1 on the right side

  11. anonymous
    • one year ago
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    oooooooooooo. The y's cancel.

  12. zepdrix
    • one year ago
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    ooo they so sneaky :D

  13. anonymous
    • one year ago
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    oooooooooooo. The y's cancel.

  14. anonymous
    • one year ago
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    Wow that's clever :P .

  15. anonymous
    • one year ago
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    Thanks!

  16. zepdrix
    • one year ago
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    \c:/

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