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anonymous
 one year ago
Simple derivative question.
anonymous
 one year ago
Simple derivative question.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I assume you implicitly differentiate and substitute in x=0 ? You'll just have an equation in terms of y then? Or am I doing something wrong?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Yah that's strange, seems like they would want you to evaluate this at some particular y'(x,y) since it's going to depend on both variables :d weird

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2But ya that sounds right, implicit, then 0 all your x's, and simplify Getting stuck on differentiating any of the pieces? :o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No I can differentiate it find. Just stuck on the actual understanding of the question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Possible to get the y value maybe?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Oh oh yes, it looks like we can get the ycoordinate that corresponds to x=0 from the original expression!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I think so at least, it looks like a lot of stuff is going to cancel out.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really? Well we then get ln(y)+y=y/2 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oooooooooooo. The y's cancel.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oooooooooooo. The y's cancel.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wow that's clever :P .
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