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En
 one year ago
WILL MEDAL AND FAN!!!
Express the surface area of a cube as a function of the length of a diagonal of one face.
En
 one year ago
WILL MEDAL AND FAN!!! Express the surface area of a cube as a function of the length of a diagonal of one face.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444471441259:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now we can use Pythagorus theorem one one face (Shown above)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444471558016:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to leave sorry, perhaps @imqwerty can help?

En
 one year ago
Best ResponseYou've already chosen the best response.0My book says that the answer is 3d^2. I dont get it :/

En
 one year ago
Best ResponseYou've already chosen the best response.0I know that the SA=6s^2 and the diagonal as √3 s.. idk how to go from there :/

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2hah XD this is not correct wait a sec i read it wrong

En
 one year ago
Best ResponseYou've already chosen the best response.0I keep solving it i only get 2d^2. The answer from my book is 3d^2. This is heartbreaking

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444473276715:dwby pythagorus theorem \[a^2+a^2=d^2\]\[2a^2=d^2\]\[a=\frac{ d }{ \sqrt{2} }\]surface area is given by\[Area=6a^2\]putting the value of a we got\[Area=6 \times \left( \frac{ d }{ \sqrt{2} } \right)^2\]\[Area=6 \times \frac{ d^2 }{ 2}\] \[Area=3d^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, i'm back. ye well done @imqwerty
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