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kittiwitti1
 one year ago
More trig questions...
ONE 
Danny and Stacey have gone from the swing to the slide at the park. The slide is inclined at an angle of a = 56.0°.
Danny weighs 40.0 pounds. He is sitting in a cardboard box with a piece of wax paper on the bottom. Stacey is at the top of the slide holding on to the cardboard box (see the figure below). Find the magnitude of the force Stacey must pull with, in order to keep Danny from sliding down the slide. (We are assuming that the wax paper makes the slide into a frictionless surface, so that the only force keeping Danny from sliding is the force with which Stacey pulls. Round your answer to one decimal place.)
FIGURE A 
http://www.webassign.net/mcktrig6/25037.gif
TWO 
Jadon is 5 years old and weighs 42.0 pounds. He is sitting on a swing when his cousin Allison pulls him and the swing back horizontally through an angle of 35.0° and then stops. Find the magnitude of the force exerted by Allison (see the figure below).
FIGURE B 
http://www.webassign.net/mcktrig7/25059.gif
kittiwitti1
 one year ago
More trig questions... ONE  Danny and Stacey have gone from the swing to the slide at the park. The slide is inclined at an angle of a = 56.0°. Danny weighs 40.0 pounds. He is sitting in a cardboard box with a piece of wax paper on the bottom. Stacey is at the top of the slide holding on to the cardboard box (see the figure below). Find the magnitude of the force Stacey must pull with, in order to keep Danny from sliding down the slide. (We are assuming that the wax paper makes the slide into a frictionless surface, so that the only force keeping Danny from sliding is the force with which Stacey pulls. Round your answer to one decimal place.) FIGURE A  http://www.webassign.net/mcktrig6/25037.gif TWO  Jadon is 5 years old and weighs 42.0 pounds. He is sitting on a swing when his cousin Allison pulls him and the swing back horizontally through an angle of 35.0° and then stops. Find the magnitude of the force exerted by Allison (see the figure below). FIGURE B  http://www.webassign.net/mcktrig7/25059.gif

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kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0FULL: ONE  http://icecream.me/f2de6848075baa9f18c05b853602d902 TWO  http://icecream.me/92037082b8d26d230ff924feb654b4e0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444474692435:dw Here theta is 56 degrees The normal reaction and mg cosine theta components balance each other, so to keep Danny in equilibrium, Stacy must apply a force mg sin theta in the opposite direction, or mg sin theta

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Question  is this physicsrelated? I was seriously about to apply my highschool physics knowledge to this xD

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0It's just that I did this once in precalculus and got a nonsensical answer, so I'm being cautious.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes this is physics related, but it uses mathematical concepts of trignometry and vector components

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My bad, trigonometry*

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0*attempts to apply physicsesque skills to problem*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444475098336:dw The magnitude of the force is simply mg cos theta since the vertical and horizontal components must balance each other for equilibrium

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry... T sin theta

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Hold on I need to work this out lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Make 2 equations and eliminate the unknown T

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also for the first part, since you only need magnitude, mg sin theta=mg sin theta

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I think the angles are mixed up on that diagram.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0This is what I got so far: dw:1444475980762:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Wait... instead of 35°, it's 34° right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope, your diagram is wrong

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0How is it wrong? And 9056=34

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Well, unless my calculator malfunctioned. *rechecks*

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444476176481:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Refer to the drawing dw:1444476245425:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is the correct diagram

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Well yeah but so is mine :T I was taught that that's step one, then transfer the angle to that part.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0But anyway regardless it's 9056=34 right? Just making sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Idk how you were taught, but that upper angle can't be 56, even in your drawing you posted it's that lower angle that is 56 Also that 35 is for another question, it's not the same slide necessarily

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0"The slide is inclined at an angle of a = 56.0°"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep, so the lower angle connecting the end of the slide with the ground will be 56, that's the inclination of the slide, at how much angle it is inclined to the ground

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0It never said the ground...

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Man, these things need to be more clear with their descriptions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0They don't need to, they have stated that it's the slide's INCLINATION, it's inclination will of course the angle it makes with the ground

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0even if you feel confused, refer to your drawing, it clearly shows what they mean by their "inclination", it's the lower angle

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Okay... Sorry, brain halfdead

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0attempts to revive it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444477065854:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry for annoying you with my reduced intellect u_u;

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh no that's absolutely fine, it can frustrating when you can't understand something

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I got the weight as 18143.1g

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0except the kid has no listed mass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\vec f=m \vec g\sin(56)=mg\sin(56)\] In terms of pound force,(lb force) \[\frac{f}{g}=m \sin(56)\] This will give the force in lb force, you are given m as 40 lbs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0acceleration due to gravity

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Wait... so mg is (x lbs) times "g" ?

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0*40 lbs times 9.81?

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I thought it was grams times G

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Weight is measured in Newtons, but for common people, it is much easier for them to identity with kilograms or pounds insteads(hence you see people saying, I weigh 70kilograms) such a statement is absolutely wrong, but is commonly used So although your answer will in units of pounds m/s^2, it is a common to practice to just express the force in units of mass, when measuring the force in units of pounds, it's called pound force and when in kilograms, it's called kilogram force When someone says I weight 70 kilogram, they mean they weight 70 kilogram force, which is 70*9.8 Newtons

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0do I convert the 40 lbs oo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So even if you get the answer is mg sin(theta), we simply divide with g, and get m sin(theta) to express in lbs, I'm saying this because earlier I saw options for your 2nd question, they were all in pounds(or poundsforce more correctly)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Didn't you find it weird?they are asking for weight(which is a force) and the options are in lbs, which is a unit of mass

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0in your previously mentioned equation, f is F force right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep, it's the force you are required to find, but you will find f/m, you will measure it in pounds

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay I kinda get it now

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I got 325.3143435 N

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u post a screenshot for options of 1st question?

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0no options. fill in blanks

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0calculation process\[\frac{F}{g}=msin56\rightarrow\frac{F}{9.81m/s^{2}}=40\sin56\]\[F=9.81\times40\sin56\approx325.3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, hmm I don't think you answer is right, let's convert the pounds to kilograms now im using a calc for this \[40 \space lbs=18.1437 \space kgs\] \[g=9.8 ms^{2}\]\[\sin(56)=0.829\] \[f=mgsin(56)=18.1437 \times 9.8 \times 0.829 = 147.403 \space N\] In terms of kilograms force \[\frac{f}{g}=18.1437 \times 0.829=15.0411 \space kg\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It will not be Newton!! the unit of mass you are using is pounds, remember that!

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0okay not newtons ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep numerically value of your answer is correct but unit is not correct, a Newton is when we are talking about kilograms, you just simply write lbs m/s^2 instead

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[325.3 \space lbf \neq 325.3 \space N\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0325.3 pound force, not newtons

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I do have a conversion of lbs to g, should I use that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Look the numerical value of your answer is correct you just need to write pounds force(lbf) instead of Newtons, we use Newton when we take mass of the body in kilograms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since you have taken mass in pounds, your answer will be in pounds force

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've got to go eat now, maybe someone else can help

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0It says it's wrong _...

phi
 one year ago
Best ResponseYou've already chosen the best response.1lbs are units of force (not mass). You can do the first problem this way. First, looking at the picture they give you, notice they show the angle \(\alpha\) is from the ground to the slide dw:1444482301947:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1Stacey pulls back with a force of 40 sin(56) to balance the force of gravity in the direction down the slide.

phi
 one year ago
Best ResponseYou've already chosen the best response.1For the 2nd problem The rope pulls up (at an angle) so that it balances the force of the weight acting straight down we can write the force of the weight as the sum of any two vectors, in particular dw:1444482908101:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1that shows the tension (force) on the rope balances the 42 lbs acting down, and the "pull" acting sideways.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I got both thanks @phi, that was very helpful
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