## anonymous one year ago A jet fighter, initially at rest, is launched from an aircraft carrier. it reaches a speed of 49m/sat the end of the catapult and this requires 3 seconds. Assuming the acceleration is constant, Whats is the length of the deck that the plane moves across?

1. anonymous

2. anonymous

lets begin by listing our knowns and unknowns. we know that the plane accelerates from 0m/s to 49 m/s in 3 seconds. so to find its acceleration all we need to do is assume that every second it will reach a third of the way to 49m/s. so we need to devide 49/3 to find the accelleration. the equation for this is $a=\frac{ v-u }{ t }$ (u) being the initial velocity which is 0. now that we have the acceleration we can substiitute it into our next equation to find the distance. $s=ut+1/2at ^{2}$ time is 3seconds as given in the question. so it accelerates at 49/3=16.33m/s/s put this value into the equation above as (a)

3. anonymous

I got 73.48m/s am I right?

4. anonymous

s=ut or 0 + 1/2(16.33)(3)^2

5. anonymous

was that what your working looked like?

6. anonymous

Yes.

7. anonymous

then it is correct

8. anonymous

(= thanks