anonymous
  • anonymous
A jet fighter, initially at rest, is launched from an aircraft carrier. it reaches a speed of 49m/sat the end of the catapult and this requires 3 seconds. Assuming the acceleration is constant, Whats is the length of the deck that the plane moves across?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
lets begin by listing our knowns and unknowns. we know that the plane accelerates from 0m/s to 49 m/s in 3 seconds. so to find its acceleration all we need to do is assume that every second it will reach a third of the way to 49m/s. so we need to devide 49/3 to find the accelleration. the equation for this is \[a=\frac{ v-u }{ t }\] (u) being the initial velocity which is 0. now that we have the acceleration we can substiitute it into our next equation to find the distance. \[s=ut+1/2at ^{2}\] time is 3seconds as given in the question. so it accelerates at 49/3=16.33m/s/s put this value into the equation above as (a)
anonymous
  • anonymous
I got 73.48m/s am I right?

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anonymous
  • anonymous
s=ut or 0 + 1/2(16.33)(3)^2
anonymous
  • anonymous
was that what your working looked like?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
then it is correct
anonymous
  • anonymous
(= thanks

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