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iwanttogotostanford

  • one year ago

hhhlll

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  1. iwanttogotostanford
    • one year ago
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    @YoungStudier @Nnesha @PrincessHush @pooja195

  2. iwanttogotostanford
    • one year ago
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    PLEASE! NEED HELP

  3. anonymous
    • one year ago
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    @surjithayer

  4. anonymous
    • one year ago
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    \[h=ut+\frac{ 1 }{ 2 }g t^2\] for each initial velocity u=0 m/s

  5. anonymous
    • one year ago
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    \[g ~t^2=2h,g=\frac{ 2h }{ t^2 }\]

  6. anonymous
    • one year ago
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    h is height t=time taken g=acceleration due to gravity

  7. iwanttogotostanford
    • one year ago
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    @surjithayer What is the acceleration due to gravity for the Earth, Moon, and Mars?

  8. iwanttogotostanford
    • one year ago
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    would t= 6.6 for the first empty slot?

  9. anonymous
    • one year ago
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    distance m=height=h Time T=t i solve first \[g=\frac{ 2*2.25 }{ \left( 0.680 \right)^2 }=?\]

  10. iwanttogotostanford
    • one year ago
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    9.7

  11. anonymous
    • one year ago
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    9.732

  12. iwanttogotostanford
    • one year ago
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    d = 1/2at2 is the equation for an object that starts at rest.

  13. iwanttogotostanford
    • one year ago
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    ok so- that is the one for the first box?

  14. iwanttogotostanford
    • one year ago
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    what would I do for the second box going horizontal?

  15. anonymous
    • one year ago
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    when the body falls from a certain height,initial velocity=0 m/s

  16. iwanttogotostanford
    • one year ago
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    So what how would I figure out acceleration due to gravity for the second box going across?

  17. anonymous
    • one year ago
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    h=3.08,t=0.793

  18. iwanttogotostanford
    • one year ago
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    so I would use that to figure out the second box?? @surjithayer

  19. anonymous
    • one year ago
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    first two values are for earth next two for Moon and last two for Mars.

  20. iwanttogotostanford
    • one year ago
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    so the very first box on the graph is 9.732 right???

  21. iwanttogotostanford
    • one year ago
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    @surjithayer

  22. anonymous
    • one year ago
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    correct

  23. iwanttogotostanford
    • one year ago
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    @surjithayer

  24. iwanttogotostanford
    • one year ago
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    please help with the rest

  25. anonymous
    • one year ago
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    Hm

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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