iwanttogotostanford
  • iwanttogotostanford
hhhlll
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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iwanttogotostanford
  • iwanttogotostanford
@YoungStudier @Nnesha @PrincessHush @pooja195
iwanttogotostanford
  • iwanttogotostanford
PLEASE! NEED HELP
anonymous
  • anonymous
@surjithayer

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anonymous
  • anonymous
\[h=ut+\frac{ 1 }{ 2 }g t^2\] for each initial velocity u=0 m/s
anonymous
  • anonymous
\[g ~t^2=2h,g=\frac{ 2h }{ t^2 }\]
anonymous
  • anonymous
h is height t=time taken g=acceleration due to gravity
iwanttogotostanford
  • iwanttogotostanford
@surjithayer What is the acceleration due to gravity for the Earth, Moon, and Mars?
iwanttogotostanford
  • iwanttogotostanford
would t= 6.6 for the first empty slot?
anonymous
  • anonymous
distance m=height=h Time T=t i solve first \[g=\frac{ 2*2.25 }{ \left( 0.680 \right)^2 }=?\]
iwanttogotostanford
  • iwanttogotostanford
9.7
anonymous
  • anonymous
9.732
iwanttogotostanford
  • iwanttogotostanford
d = 1/2at2 is the equation for an object that starts at rest.
iwanttogotostanford
  • iwanttogotostanford
ok so- that is the one for the first box?
iwanttogotostanford
  • iwanttogotostanford
what would I do for the second box going horizontal?
anonymous
  • anonymous
when the body falls from a certain height,initial velocity=0 m/s
iwanttogotostanford
  • iwanttogotostanford
So what how would I figure out acceleration due to gravity for the second box going across?
anonymous
  • anonymous
h=3.08,t=0.793
iwanttogotostanford
  • iwanttogotostanford
so I would use that to figure out the second box?? @surjithayer
anonymous
  • anonymous
first two values are for earth next two for Moon and last two for Mars.
iwanttogotostanford
  • iwanttogotostanford
so the very first box on the graph is 9.732 right???
iwanttogotostanford
  • iwanttogotostanford
@surjithayer
anonymous
  • anonymous
correct
iwanttogotostanford
  • iwanttogotostanford
@surjithayer
iwanttogotostanford
  • iwanttogotostanford
please help with the rest
anonymous
  • anonymous
Hm

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