A ball is thrown 28.85 meters horizontally. It has an original velocity in the "X" direction of 11m/s find the time the ball was in the air and the theight in the "Y" direction.
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ITS 24.85meter INSTEAD OF 28.85meter
to the horizontal direction since there is no acceleration with use of S=ut you can find the time spent
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the same time which is found from the above method is taken for the ball to reach the ground from top. Since at the start the balll only had a horizontal velocity (no vertical velocity) you can use another equation to find the travelled vertical distance by applying the equation to the vertical direction