## anonymous one year ago Can someone help me with the last one on the second row? http://prntscr.com/8pjizy

1. anonymous

y-5=-2(x+1)^2 $y=5-2\left( x+1 \right)^2=\left( \sqrt{5} \right)^2-\left\{ \sqrt{2}\left( x+1 \right) \right\}^2$ $y=\left\{ \sqrt{5}+\sqrt{2}\left( x+1 \right) \right\}\left\{ \sqrt{5}-\sqrt{2}\left( x+1 \right) \right\}$ $or ~y=-\left( \sqrt{2}x+\sqrt{2}+\sqrt{5} \right)\left( \sqrt{2}x+\sqrt{2} -\sqrt{5}\right)$

2. Michele_Laino

furthermore, if we develop the square of binomial at the rifght side, we can write this: $y = 5 - 2{x^2} - 2 - 4x = ...?$ please complete the computation above

3. Michele_Laino

right* side