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owlet
 one year ago
A gaseous reaction occurs at a constant pressure of 50.4 bar and releases 67.0 kJ of heat. Before the reaction, the volume of the system was 9.00 L . After the reaction, the volume of the system was 2.20 L .
Calculate the total internal energy change, ΔU, in kilojoules.
owlet
 one year ago
A gaseous reaction occurs at a constant pressure of 50.4 bar and releases 67.0 kJ of heat. Before the reaction, the volume of the system was 9.00 L . After the reaction, the volume of the system was 2.20 L . Calculate the total internal energy change, ΔU, in kilojoules.

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owlet
 one year ago
Best ResponseYou've already chosen the best response.0So I know.. ΔU = q + W and W =  PΔV q=67.0 kJ ΔV = 2.209L= 6.8L P= 50.4 bar I also know 1 L•bar = 100 J Substituting all my given values: ΔU = q + W ΔU = 67.0 kJ + (50.4 bar)(6.8 L ) ΔU = 67.0 kJ + 342.72 L•bar ΔU = 67.0 kJ + 34.272 kJ ΔU = 32.728 kJ AM I RIGHT?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2yep! you got the signs and everything right, it looks right (as long as you didn't make a mistake multiplying or something)

owlet
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you! I just wanted to make sure that it is right :)

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2no problem! is this from a textbook? they usually have answers at the back, or you can download the solution manual
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