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## anonymous one year ago pi is polynomial?

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1. owlet

no, it is irrational. polynomials contain variables that have different exponents on them

2. freckles

constants are still polynomials

3. freckles

$a_n x^{n}+a_{n-1}x^{n-1}+ \cdots a_2 x^2+a_1 x_1+a_0 \text{ is a polynomial } \\ \text{ where } n \text{ is a positive integer } \\ \text{ and } a_i \text{ is a real number }$

4. freckles

And I guess you could define polynomials with complex coefficients instead

5. freckles

And above I mean to say all the exponents are either positive integers or zero

6. anonymous

ok

7. anonymous

Pi is not a polymonial. It is an irrational number.

8. anonymous

Like freckles said.

9. freckles

no I was saying pi a polynomial

10. freckles

constants are polynomials

11. freckles

pi is a constant

12. freckles

pi is a irrational number I agree with that but pi is also a polynomial

13. anonymous

Oh.

14. anonymous

But aren't polymonials equations, usually?

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