How do you get the derivative of y=3(x^2 + 2x)^2 using the chain rule. Please show step by step.

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How do you get the derivative of y=3(x^2 + 2x)^2 using the chain rule. Please show step by step.

Mathematics
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\(\large y=3(x^2 + 2x)^2 \) You first take the derivative of the outer, then take the derivative of the inside. Hint: The outer needs just the power rule and the inner needs the power rule as well. I will start by taking the derivative of the outer. \(\large \frac{dy}{dx}=3*2((x^2 + 2x))^{2-1} *\frac{d}{dx}(x^2 + 2x)\)
Can you finish it from there?
Chain rule is done my taken the derivative of the outer and multiply the inner derivatives.

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Yes, thank you!
\(\frac{dy}{dx}=\frac{d}{dx}3(x^2 + 2x)^{2}*\frac{d}{dx}(x^2 + 2x)\)
No problem!

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