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mathmath333
 one year ago
One ball is drawn at random from any of the 2 buckets
find the probablity of this ball being blue ?
mathmath333
 one year ago
One ball is drawn at random from any of the 2 buckets find the probablity of this ball being blue ?

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444496382465:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{One ball is drawn at random from any of the 2 buckets}\hspace{.33em}\\~\\ & \normalsize \text{ ,find the probablity of this ball being blue ?}\hspace{.33em}\\~\\ \end{align}}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0hmm i think :P number of blue ballz over total number of ballz :D

mom.
 one year ago
Best ResponseYou've already chosen the best response.1suppose we put both the buckets in a sack and then take the ball out its the same as taking a blue ball out of 26 balls having 14 blue ones (; so probability=14/26 =7/13 (;

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{Answer given is}\ \dfrac{41}{77} \hspace{.33em}\\~\\ \end{align}}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0there are 25 ballz not 26 13 blue balls 12 red hm

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0It is not given that u should put the balls in a single sac

freckles
 one year ago
Best ResponseYou've already chosen the best response.4we need bayes theorem

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[P(blue)=P(bluebucket 1) \cdot P(bucket 1)+P(bluebucket 2) \cdot P(bucket2)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4dw:1444498209882:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[P(blue)=\frac{6}{14} \cdot \frac{1}{2}+\frac{7}{11} \cdot \frac{1}{2}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4in a similar way we can find P(red) \[P(red)=P(redbucket 1) \cdot P(bucket 1)+P(redbucket 2) \cdot P(bucket2) \\ P(red)=\frac{8}{14} \cdot \frac{1}{2}+\frac{4}{11} \cdot \frac{1}{2}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4oops I guess we could have just done 1P(blue) but whatever

welshfella
 one year ago
Best ResponseYou've already chosen the best response.11/2 * 3/7 + 1/2 * 7/11 = 41/77
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