A box has 60 balls, of which 26 are red, 16 are blue, and 18 are yellow. Balls are extracted at random then returned to the box. What is the probability that after performing this test three times exactly two are red and one is yellow?

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A box has 60 balls, of which 26 are red, 16 are blue, and 18 are yellow. Balls are extracted at random then returned to the box. What is the probability that after performing this test three times exactly two are red and one is yellow?

Mathematics
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a tree diagram would help with this one
ok
is answer \(\dfrac{169}{1125}\)

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Other answers:

i dont how u got that answer im just thinking about the tree @welshfella said
i mean is the answer already given in book
its hard to draw a tree diagram with 3 draws!!! lol
perhaps u can attaches as a image file lol
possible scenarios are R R Y R Y R Y R R probability of each of these is 26/60 * 26/60 * 18 / 60 work this out then multiply it by 3
121168/180
you have made a mistake somewhere
i see
12168/216000
169/3000
26/60 * 26/60 * 18 / 60 = 13/30 * 13/30 * 3/10 = 507 / 9000
= 169/1000 yes
now you need to multiply that by 3 because of the 3 different arrangements of the balls)
169/1000 or 169/3000?
sorry its |dw:1444498605068:dw|
507/3000
169/3000 was correct for each of th 3 scenarios - now you need to multiply that by 3
507/3000 is correct but that simplifies to 169/1000
mistake sorry 169/1000, forget to cancelled out the 3
yea that is it
that the final answer ?
yes
ok thank you so much for the help
yw

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