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anonymous

  • one year ago

Three disjoint subsets are to be formed from a collection of 30 items. The first is to have 10 elements, the second is to have 9 elements, and the third is to have 11 elements. In how many ways can this be done?

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  1. anonymous
    • one year ago
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    somehow my answer doesnt match up the answer from the book, strange

  2. anonymous
    • one year ago
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    \[\left(\begin{matrix}30 \\ 10\end{matrix}\right), \left(\begin{matrix}30 \\ 9\end{matrix}\right),\left(\begin{matrix}30 \\ 11\end{matrix}\right)\]

  3. anonymous
    • one year ago
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    I got 989779465 but the book answer is 5046360719400

  4. amistre64
    • one year ago
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    does order matter?

  5. amistre64
    • one year ago
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    i think 30C10, then after 10 are chosen its 20C9, etc

  6. amistre64
    • one year ago
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  7. amistre64
    • one year ago
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    \[\binom{n}{a}\binom{n-a}{b}\binom{n-a-b}{c}...\]

  8. anonymous
    • one year ago
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    k thank you for the clarification

  9. amistre64
    • one year ago
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    yw

  10. anonymous
    • one year ago
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    Three disjoint subsets are to be formed from a collection of 30 items. The first is to have 11 elements, the second is to have 9 elements, and the third is to have 10 elements. In how many ways can this be done? that will give the same answer?

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