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anonymous

  • one year ago

Quadratic formula. I can't seem to figure it out. I'll become a fan and give a medal

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  1. zepdrix
    • one year ago
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    Do you have a specific example that we need to use the Formula on? :)

  2. anonymous
    • one year ago
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    hold on i'm attaching a file

  3. anonymous
    • one year ago
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  4. zepdrix
    • one year ago
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    \[\large\rm \color{green}{1}x^2+\color{orangered}{9}x+\color{royalblue}{10}=0\]And our formula is,\[\large\rm x=\frac{-\color{orangered}{b}\pm\sqrt{\color{orangered}{b}^2-4\color{green}{a}\color{royalblue}{c}}}{2\color{green}{a}}\]ya? :o Understand why I put a 1 on the x^2?

  5. anonymous
    • one year ago
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    nope. I suck at geometry

  6. anonymous
    • one year ago
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    A = 1 B = 9 C = 10

  7. anonymous
    • one year ago
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    also remember that if B is a negative i.e -9 then it would be +b rather than -b at the start

  8. anonymous
    • one year ago
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    \[\frac{-9\pm \sqrt{9^2-4*1*10} }{2*1 }\]

  9. anonymous
    • one year ago
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    \[X _{1} = \frac{ -9+\sqrt{41} }{2 } X _{2} = \frac{ -9-\sqrt{41} }{ 2 }\]

  10. anonymous
    • one year ago
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    Tbh @Lily2913 I don't understand any of that

  11. anonymous
    • one year ago
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    ok it's B

  12. anonymous
    • one year ago
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    -7.7, -1.3

  13. anonymous
    • one year ago
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    Thank you so so so so much. I've literally been working on that problem for an hour

  14. anonymous
    • one year ago
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    Quadratic formula gives you 2 results X1 and X2 so if you had put the above in your calculator you would have seen -7.7 and -1.3

  15. anonymous
    • one year ago
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    I hope you get a hang of it before any exams you need to take that use it. :)

  16. anonymous
    • one year ago
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    IKR currently i'm screwed

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spraguer (Moderator)
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