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calculusxy

  • one year ago

Solving equation with quadratic formula. Question will be given below

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  1. calculusxy
    • one year ago
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    \[\large 2x^2 - 5x = 52\]

  2. calculusxy
    • one year ago
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    I know that the quadratic formula is: \[\large x = \frac{ -b \pm \sqrt{b^2 - 2ac} }{ 2a }\]

  3. amistre64
    • one year ago
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    a quadratic equation of the form: ax^2 + bx + c = 0 has roots defined by the quadratic formula as: \[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\] which is just a shortcut of completing the square

  4. calculusxy
    • one year ago
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    \[\large x = \frac{ -(-5) \pm \sqrt{(-5)^2 - 2(2)(-52)} }{ 2(2) }\] if i solve it like this will it be fine?

  5. calculusxy
    • one year ago
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    @Nnesha @amistre64

  6. amistre64
    • one year ago
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    might be a typo, but its 4ac, not 2ac

  7. amistre64
    • one year ago
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    otherwise your values for abc are good

  8. calculusxy
    • one year ago
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    ok

  9. calculusxy
    • one year ago
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    \[x = \frac{ 5 \pm \sqrt {25 + 208} }{ 4 }\]

  10. calculusxy
    • one year ago
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    if solve it with this will it be correct? @amistre64

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