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ParthKohli
 one year ago
A gas undergoes a process such that the ratio of P and V is constant and equal to one. What's the molar heat capacity?
ParthKohli
 one year ago
A gas undergoes a process such that the ratio of P and V is constant and equal to one. What's the molar heat capacity?

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ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[dw:1444507155788:dw\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[C_{m} = \frac{\partial q }{\partial T}\]Is this relation right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0MATH PROCESSING ERROR

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1That drawing isn't important. Just a PV graph with slope one.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[q = \Delta U  w\]\[= \frac{3}2RT + pV = \frac{3}{2}RT + RT =\frac{5}{2}RT\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1I don't think it's 5R/2 though.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Looks like I nowhere used the fact that \(p=V\).

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0I suspect \(w=\int p(t)V(t)\,dt=\int p(t)^2\,dt\).

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Oh, what a stupid mistake.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{pV}{2}=\frac{p^2}{2}= \frac{V^2}{2}\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1then we're done here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0WHY IS MATH NOT PROCESSING

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0So the answer is 3/2R?
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