MEDAL!!! Question will be posted below.

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MEDAL!!! Question will be posted below.

Mathematics
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\[\huge v^2 - 20 = 0 \]
Solve with quadratic formula
ok have you tried anything yet ?

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yes gimme a moment
okay
\[\frac{ -b \pm \sqrt{b^2-4ac}}{ 2a } \]
\[\frac{ -0 \pm \sqrt{0 - 4(-20)} }{ 2 }\]
yes
i thought the new equation would be like: \[v^2 + 0a - 20 = 0\]
\[\frac{ -0 \pm 8.9 }{ 2 }\]
0v would be better, but yes. v^2 +0v -20 = 0
v^2 -20 is same as `v^2 -0v -20`
well would be great if get the final answer in radical
don't take square of 20 factor it out
square root*
the answer key for this in decimal form...
oh okay then.
\[\frac{ -0 \pm 8.9 }{ 2 } = 4.45 \]
remember it's \[\pm \]
okay so -4.45 or 4.45
yes
^ye right it's \[\rm a \pm b ~= a-b ~~ and ~a+b\]
is my answer correct?
yes it is. if your key says 4.4721... it's only because you cut off some decimals from 8.9
i didn't get 4.4 `5`
but you did solve it correctly.
ok thank you :)

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