## anonymous one year ago For the reaction 2A+B=C+2D, the starting [A]=4.0M and [B]=3.0. At equilibrium the [C]=1.0M. Calculate the value of the equilibrium constant, K(c). I tried the formula but go no where because of "2D". Thank-you. a.)0.5 b.)2.0 c.)3.0 d.)3.5

1. anonymous

2. anonymous

@jebonna

3. anonymous

@Cuanchi

4. cuanchi

you have to do an ICE table, are you familiar with that?

5. anonymous

No I am not, i'm sorry.

6. cuanchi

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7. cuanchi

I= initial C= change E= equilibrium

8. anonymous

Oh! yes, yes! but I am to given one. Only that statement.

9. cuanchi

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10. anonymous

But how did you come up with those numbers?

11. anonymous

Wait are those the coefficients?

12. anonymous

So [1][2]/[2]^2[1]=.5?????

13. cuanchi

the problem said that you have at the equilibrium 1M of C. You have to assume that was 0 M of C at the beginning and 1 mole was produced. Then by the stoichiometry of the reaction you can calculate how much of A and B has to be consume to produce 1 mol of C.

14. cuanchi

no

15. cuanchi

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16. anonymous

OMG thank-you!!!!! so simple.

17. anonymous

@Cuanchi can I ask you another question?

18. cuanchi

sure if it fast

19. anonymous

20. cuanchi

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21. cuanchi

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22. Jhannybean

I was trying to upload a picture of what I did as well xD

23. cuanchi

isolate the "x" that is just math

24. cuanchi

i got to go sorry

25. anonymous

thank you so much!

26. cuanchi

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27. cuanchi

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