iwanttogotostanford
  • iwanttogotostanford
I
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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iwanttogotostanford
  • iwanttogotostanford
@zepdrix @triciaal
iwanttogotostanford
  • iwanttogotostanford
I need to know the acceleration due to gravity and the average G value for each of them given what I have
iwanttogotostanford
  • iwanttogotostanford
E Earth Moon Mars Distance (m) 2.25 3.08 4.04 4.57 4.68 3.55 Time (s) 0.680 0.793 2.20 2.26 1.58 1.38 Acceleration due to Gravity (m/s^2) 9.732 9.795 1.669 1.789 3.749 3.728 Average G value for the location (m/s^2)

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iwanttogotostanford
  • iwanttogotostanford
I NEED TO KNOW THE AVERAGE G VALUE FOR THE LOCATION
iwanttogotostanford
  • iwanttogotostanford
I need the equation or formula please I am confused
jdoe0001
  • jdoe0001
a picture of the chart/table will work better methinks but the acceleration could be obtained from the slope I'd think
jdoe0001
  • jdoe0001
and average... is more or less rate of change, which brings us back to slope again
iwanttogotostanford
  • iwanttogotostanford
Earth Moon Mars Distance (m) 2.25 3.08 4.04 4.57 4.68 3.55 Time (s) 0.680 0.793 2.20 2.26 1.58 1.38 Acceleration due to Gravity (m/s^2) 9.732 9.795 1.669 1.789 3.749 3.728 Average G value for the location (m/s^2)
jdoe0001
  • jdoe0001
then again, a picture of the table woiuld help :)
iwanttogotostanford
  • iwanttogotostanford
This is the chart but it looks a little messed up but it is in line
jdoe0001
  • jdoe0001
well, surely doesn't look like that on your screen... so just screenshot it methink
iwanttogotostanford
  • iwanttogotostanford
I'm on a macbook
iwanttogotostanford
  • iwanttogotostanford
but I will try
iwanttogotostanford
  • iwanttogotostanford
iwanttogotostanford
  • iwanttogotostanford
Here it is
iwanttogotostanford
  • iwanttogotostanford
it is a download did you get it
anonymous
  • anonymous
http://prntscr.com/8q0dt3 There's a screenshot if you can't download the document for some strange reason. For future reference, press command + shift + 4 to screenshot something on a Mac.
jdoe0001
  • jdoe0001
yes.... well you have two values per each location so the average "G"ravity will be the sum of both, divided by 2 say for earth will be \(\bf \cfrac{9.732+9.795}{2}\)
iwanttogotostanford
  • iwanttogotostanford
So would they be in order= 14.6295 2.5635 5.613
iwanttogotostanford
  • iwanttogotostanford
@jdoe0001
iwanttogotostanford
  • iwanttogotostanford
@jdoe0001 Please check
iwanttogotostanford
  • iwanttogotostanford
@triciaal Did i do the table right?? :-)
triciaal
  • triciaal
no idea haven't look yet
iwanttogotostanford
  • iwanttogotostanford
@triciaal could you check please
triciaal
  • triciaal
not sure of final for each location same process velocity = distance /time acceleration = velocity/time for Earth (3.08 - 2.25)/ (0.793-0.680) = velocity velocity/time(1) = 9.732 velocity/time(2) = 9.795 average G = velocity/(t2 - t1)
triciaal
  • triciaal
|dw:1444528438601:dw|
triciaal
  • triciaal
@mathmate can you help with this?
triciaal
  • triciaal
@jim_thompson5910 ?
mathmate
  • mathmate
@iwanttogotostanford You would need the kinematics equation for an object in free fall, \(\Delta x= (1/2)gt^2\) where g=acceleration due gravity, t=time it takes, (initial velocity = 0 for free fall) Solve for g to get \(g=2\Delta x /t^2\) That's how @jdoe001 got 9.732 and 9.795 for the first pair of data. Continue with the two other pairs for moon and mars, and you'll have a nice table.
mathmate
  • mathmate
Average value would be, as @jdoe0001 stated, the sum divided by 2, for each pair.
iwanttogotostanford
  • iwanttogotostanford
@mathmate I know but what about for the last row of the table- i am confused
iwanttogotostanford
  • iwanttogotostanford
@triciaal
iwanttogotostanford
  • iwanttogotostanford
@jim_thompson5910 how do you figure out the last row i know the third row but did i do the last row correctly?
mathmate
  • mathmate
Location Earth Moon Mars Acceleration due to Gravity (m/s^2) \(\color{red}{(}\)9.732 9.795\(\color{red}{)}\) \(\color{red}{(}\)1.669 1.789\(\color{red}{)}\) \(\color{red}{(}\)3.749 3.728\(\color{red}{) }\) Average acceleration 9.764 1.729 3.739 For earth, the average is (9.732+9.795)/2=9.764 For moon, the average is (1.669+1.789)/2=1.729 For mars, the average is (3.749+3.728)/2=3.739

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