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quickstudent

  • one year ago

Can someone please help me with factoring sum of cubes?

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  1. quickstudent
    • one year ago
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  2. jim_thompson5910
    • one year ago
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    part a) is incorrect

  3. jim_thompson5910
    • one year ago
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    |dw:1444519240508:dw|

  4. jdoe0001
    • one year ago
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    hmmmm you'd be doing the same thing @Directrix alrready suggested http://openstudy.com/study#/updates/561990efe4b086e96bfef34b just do an addition of cubes \(\textit{difference of cubes} \\ \quad \\ a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad (a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\ a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad (a-b)(a^2+ab+b^2)= a^3-b^3\)

  5. jdoe0001
    • one year ago
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    Jhannybean ahemm, sake of order =)

  6. Jhannybean
    • one year ago
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    Oh hahaha Ok \(\checkmark\) I thought it was to trick my eyes.

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spraguer (Moderator)
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