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anonymous
 one year ago
I'm trying to find what the summation from 0 to infinity of ((e^4)4^x)/4! converges to (trying to show it is a valid pdf). Any suggestions on how to approach this would be welcome.
anonymous
 one year ago
I'm trying to find what the summation from 0 to infinity of ((e^4)4^x)/4! converges to (trying to show it is a valid pdf). Any suggestions on how to approach this would be welcome.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \sum_{0}^{\infty} \frac{4^x(e^{4})}{4!}\] Is it this? haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm dunno that one :(

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1does the sequence limit to zero?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1e^(4)/4! is just some constant value ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I believe it does, since the factorial grows faster than the exponential

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh sorry it's over x!

amistre64
 one year ago
Best ResponseYou've already chosen the best response.14^x is the only thing that varies .. the constant factors out ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you're right, without that it wouldn't converge

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1.... can you pic the question? avoids alot of error

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[p(x) = \frac{e^{4}4^x}{x!}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1pdf, probability density function ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, pmf not pdf. sorry, the pic was coming out really grainy

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we want the sumto equal ...1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know i can pull out the constant

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1then it behooves us to consider that 4^x/x! = e^(4)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1do you recall the taylor series for e^x ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't i can look it up, that may be the prod in the right direction i am looking for

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1its a thought, not sure how well it will turn out tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ah, yes. that looks like it exactly

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[e^x = \sum \frac{x^n}{n!}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1im so clever it scares me ....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha i liked how you looked at it in terms of solving for what would give us e^4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i appreciate the help
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