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anonymous
 one year ago
Please help!....a root of x^25x1=0 is
A. 1√29/2
B. 5√17/2
c. 1+ √29/2
D. 5+ √17/2
E. 5 +√29/2
anonymous
 one year ago
Please help!....a root of x^25x1=0 is A. 1√29/2 B. 5√17/2 c. 1+ √29/2 D. 5+ √17/2 E. 5 +√29/2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0uze das kuadratik phormula :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \textit{quadratic formula}\\ {\color{blue}{ 1}}x^2{\color{red}{ 5}}x{\color{green}{ 1}}=0 \qquad \qquad x= \cfrac{  {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\) see what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^25x1=0\]\[(x^25x)=1\]\[x^25x\color{reD}{+\frac{25}{4}} = 1\color{red}{+\frac{25}{4}}\]\[\left(x\frac{5}{2}\right)^2=\frac{29}{4}\]\[x=\pm \frac{\sqrt{29}}{2} +\frac{5}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To find the portion in red is like completing the quadratic formula on the LHS, \(c=\left(\dfrac{5}{2}\right)^2 = \dfrac{25}{4}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks So much I just checked and its right!
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