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- genny7

Help! Please!
-8-4-(-2)-(+2)(-3)

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- genny7

Help! Please!
-8-4-(-2)-(+2)(-3)

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- MrNood

first you must put any 'minus' signs inside the brackets they refer to.
Rewrite the sum with the brackets evaluated...

- MrNood

(btw - have you missed out a + or - between the last 2 brackets?)

- genny7

This is order of operations

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- MrNood

and first is B for brackets
so do what I suggested first

- genny7

@MrNood Im stuck

- anonymous

It can either be PEDMAS or BEDMAS P = Parentheses B = Bracket

- anonymous

Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

- genny7

Okay but i keep getting -16 & in my book it has a different answer

- anonymous

-8-4-(-2)-(+2)(-3) so using the rules we see that ((+2)(-3) would come first

- genny7

Yes and that would be -6 right

- anonymous

so then you have -8-4-(-2)-(-6)

- anonymous

right now do the multiplication of -1*(-2) and -1*(-6)

- anonymous

so that should give you -8-4+2+6

- anonymous

from there you can just do -8-4 = -12 and 2+6 = 8 and add the results together

- genny7

Okay i think i got it from there

- mathstudent55

This is an "order of operations" problem.
In this case, the parentheses are here for only two reasons:
1) to separate a negative sign from an addition sign
2) to show a product
Using PEMDAS, you can skip PE, and go right to
MDAS which means the following:
MD - multiplications and divisions in the order they appear from left to right
AS - additions and subtractions in the order they appear from left to right
\(-8-4-(-2)-(+2)(-3)\)

- mathstudent55

\(-8-4-(-2)-\color{red}{(+2)(-3)}\)
The operation shown in read above is a multiplication, so it has to be done first.
\(= -8-4-(-2)-\color{red}{(-6)}\)
Now all you have left is subtractions, so do them in order from left to right, one at a time.
\(= -8-4-(-2)-(-6)\)
\(= -12-(-2)-(-6)\)
\(= -10-(-6)\)
\(= -4\)

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