genny7
  • genny7
Help! Please! -8-4-(-2)-(+2)(-3)
Mathematics
chestercat
  • chestercat
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MrNood
  • MrNood
first you must put any 'minus' signs inside the brackets they refer to. Rewrite the sum with the brackets evaluated...
MrNood
  • MrNood
(btw - have you missed out a + or - between the last 2 brackets?)
genny7
  • genny7
This is order of operations

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MrNood
  • MrNood
and first is B for brackets so do what I suggested first
genny7
  • genny7
@MrNood Im stuck
anonymous
  • anonymous
It can either be PEDMAS or BEDMAS P = Parentheses B = Bracket
anonymous
  • anonymous
Parentheses, Exponents, Multiplication, Division, Addition, Subtraction
genny7
  • genny7
Okay but i keep getting -16 & in my book it has a different answer
anonymous
  • anonymous
-8-4-(-2)-(+2)(-3) so using the rules we see that ((+2)(-3) would come first
genny7
  • genny7
Yes and that would be -6 right
anonymous
  • anonymous
so then you have -8-4-(-2)-(-6)
anonymous
  • anonymous
right now do the multiplication of -1*(-2) and -1*(-6)
anonymous
  • anonymous
so that should give you -8-4+2+6
anonymous
  • anonymous
from there you can just do -8-4 = -12 and 2+6 = 8 and add the results together
genny7
  • genny7
Okay i think i got it from there
mathstudent55
  • mathstudent55
This is an "order of operations" problem. In this case, the parentheses are here for only two reasons: 1) to separate a negative sign from an addition sign 2) to show a product Using PEMDAS, you can skip PE, and go right to MDAS which means the following: MD - multiplications and divisions in the order they appear from left to right AS - additions and subtractions in the order they appear from left to right \(-8-4-(-2)-(+2)(-3)\)
mathstudent55
  • mathstudent55
\(-8-4-(-2)-\color{red}{(+2)(-3)}\) The operation shown in read above is a multiplication, so it has to be done first. \(= -8-4-(-2)-\color{red}{(-6)}\) Now all you have left is subtractions, so do them in order from left to right, one at a time. \(= -8-4-(-2)-(-6)\) \(= -12-(-2)-(-6)\) \(= -10-(-6)\) \(= -4\)

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