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anonymous

  • one year ago

5. Multiply 9x^2(2x^2 + 8x). A) 18x^4 + 72^3 B) 18x^2 + 72x^3 C) 11x^4 = 17x^3 D) 90x^4

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  1. anonymous
    • one year ago
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    I need help with this one as well 6. Factor the following polynomial completely: 30y^6 + 25y^5 - 10y^4. A) 10y^4 (3y^2 + 2y - 1) B) 5y (6y^4 + 5y^3 - 2y^2) C) 5 (6y^6 + 5y^5 - 2y^4) D) 5y^4 (6y^2 + 5y - 2)

  2. anonymous
    • one year ago
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    if you distribute the 9x^2 you'll get 9x^2*2x^2 + 9x^2*8x

  3. Directrix
    • one year ago
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    |dw:1444526248540:dw|

  4. Directrix
    • one year ago
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    |dw:1444526394549:dw|

  5. Directrix
    • one year ago
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    @Answers101 What is the answer in multiplying 9 * 2 * x^2 * x^2 ?

  6. anonymous
    • one year ago
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    @Directrix 18x^4 + 72x^3

  7. Directrix
    • one year ago
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    I think so. Just a second.

  8. Directrix
    • one year ago
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    |dw:1444526679633:dw|

  9. anonymous
    • one year ago
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    @Directrix Thanks :)

  10. Directrix
    • one year ago
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    Yes, your answer is correct. You are welcome.

  11. Directrix
    • one year ago
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    What about this? Have you done it yet? 30y^6 + 25y^5 - 10y^4

  12. anonymous
    • one year ago
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    @Directrix Yes I got D

  13. anonymous
    • one year ago
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    |dw:1444537784611:dw|

  14. Directrix
    • one year ago
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    Option D is what I got after I factored out the common monomial factor. What was left, (6y^2 + 5y -2) did not factor over the set of integers.

  15. Directrix
    • one year ago
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    |dw:1444527097833:dw|

  16. Directrix
    • one year ago
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    At first, I thought it was a 3. D) 5y^4 (6y^2 + 5y - 2)

  17. anonymous
    • one year ago
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    Yeah I know it looks like a 3 I meant for it to look like a -2

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