anonymous
  • anonymous
can someone explain this to me?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
are you trying to solve for m?
anonymous
  • anonymous
yes theres some options a. m = 4 b. m = 2 c. m = 6 d. m = -2
anonymous
  • anonymous
ok well here you should start by distributing the -4 so -4*-3m = 12m and -4 *(-2) = 8 which means you now have 12m+8=32

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anonymous
  • anonymous
you can subtract 8 from both sides like this 12m +8 -8 = 32 - 8
anonymous
  • anonymous
so now you have 12m=24 and now you can divide 12 from both sides
anonymous
  • anonymous
\[\frac{ 12m }{ 12 } = \frac{ 24 }{ 12 }\] leaving you with m = 24/12
anonymous
  • anonymous
which is 2
anonymous
  • anonymous
? i believe
anonymous
  • anonymous
it's like the circle question you did when you had to move the 2π around
anonymous
  • anonymous
yes
anonymous
  • anonymous
yeah i think they are all the same these just confuse me
anonymous
  • anonymous
once you get the hang of rules of algebra you'll have no issues with this stuff. :)
anonymous
  • anonymous
just always remember "What you do to one side of an equation you must do to the other side."
anonymous
  • anonymous
i hope! theres a couple like this do you mind?
anonymous
  • anonymous
cause i kind of get it but then when i'm left to do it alone I have no idea
anonymous
  • anonymous
go for it
anonymous
  • anonymous
What is the solution to -(-5 - 6x) = 4(5x + 3)? Select one: a. x = -2 b. x = -1/2 c. x = 2 d. x = 1/2
anonymous
  • anonymous
oh!! i remember dat one, x= -1/2, right teehee|dw:1444597877958:dw|
anonymous
  • anonymous
-(-5 - 6x) = 4(5x + 3)\[(-1)(-5-6x) = 5+6x \]\[ 4(5x +3) = 20x+12 \] from here you now have 5+6x = 20x +12 you want to get all the x terms on one side and all the non x terms on the other so it becomes 6x-20x = 12-5 which when combined is -14x = 7 now divide -14 from both sides and you'll have \[x = -\frac{ 7 }{14 }\]
anonymous
  • anonymous
simplify and you will have \[x = -\frac{ 1 }{ 2 }\]

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