(y-y1)=m(x-x1)

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what about it ?? :=)
do you know the answer?
well i need the statement ? what they are asking ?? do you have points to plugin ?

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that is the point slope equation for a line. What is your question?
you see im really horrible at this and i don't even have a clue about what you asked but i think i do you mean the missing numbers?
ita asking me what represents the line in the slope
do you have graph ? maybe we have to find numbers from the graph
\[\rm (y-y_1)=m(x-x_1)\] is point slope form where m represent slope y=mx+B slope intercept form where m is slope and b is y-intercept
you would use that formula and 2 points which have X and Y coordinates to get the equation for the line that connects both points and M is the slope
i figured it out it was y+6=4(x-3)
good we need to convert that into slope intercept form ??
i think thats what it wants?
cause im basically finding the point slope form
hmm alright \[\huge\rm y+6=4(x-3)\] start with distributive property distribute (x-3) by 4 here is an example \[\rm \color{ReD}{a}(b+c)=\color{ReD}{a}*b+\color{ReD}{a}*c =\color{ReD}{a}b+\color{Red}{a}c\]
thats equation is already in point slope form \[\huge\rm y-y_1 = m(x-x_1)\] ^^^ point slope form \[\huge\rm y=mx+b\] ^ slope intercept form \[\huge\rm Ax+By=C\] ^standard form of linear equation
y+6 = 4x - 12 from there you can solve for y by subtracting 6 from both sides.
thank you!
got it ?
yeah i figured it out!

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