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Have you tried using IVT ?

Noo. I'm not sure where to start.

I don't know what IVT is o.o

find that the function has a positive and a negative value

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Ahh k. ^ makes sense thus far.

degree of 5? hm?

Look at the equayion in problem #56
first convinvce yourself that it is a polynomial equation

just do this f(10000) = positive
f(-1000000) = negative
you are done

the curve* must pass if u are picky -.-

Haha k. Well, what does it mean for it to have a real root? that just means it passes through 0?

thats what a root is

a real root means u have an x value where that intersects the x axis

real roots are same as x intercepts in the graph

highest is odd degree* polynomial

even highest degree polynomials dont need to have real root

I see, I see. Ok, this is making much more sense.

you might need more support, the better way is to show that htere is a positive and a negative value

and say since its continuous.. it must pass thru xaxis

pale*

hm ok. Should I do any equations to prove it?

so u have shown that this functions goes to inf and -inf at its end points

hmm ok. Why did you add all those extra numbers? o.o

the abcd?

Yeah. If the original is: x^5-x^2+2x+3

its just more general, u can plug in the values for a b c d respectively

i couldnt remember your question exactly so

^ thanks so much. I think I get it :) looking over notes and looking at all you said.