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owlet
 one year ago
My answer is wrong. Can anyone check my solution? I got approx, 490 N but the correct answer is 550N. Why is that? I'll attached both the question and my solution.
owlet
 one year ago
My answer is wrong. Can anyone check my solution? I got approx, 490 N but the correct answer is 550N. Why is that? I'll attached both the question and my solution.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the answer highlighted in yellow?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lets get forces in terms of their x and y components

owlet
 one year ago
Best ResponseYou've already chosen the best response.1F1 first... F1x= 850(4/5)=680 F1y= 850(3/5)=510 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep or we can write it as\[F _{1}=\left[ 680i510j \right] {\space}kN\]

owlet
 one year ago
Best ResponseYou've already chosen the best response.1oh okay.. next f2: F2x= 625sin(30)=312.5N F2y=625cos(30)=541.3N oh i think this is the part i got wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F _{2}=\left[ (625\sin30)i(624\cos30)j \right] kN\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0remember unit circle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444531507696:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in the third quadrant, only tan is positive, hence since and cos are negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F _{2}=\left[ 312.5i541.3j \right]{\space} \]

owlet
 one year ago
Best ResponseYou've already chosen the best response.1okay.. F3: F3x=750 sin(45)=530.33 N (x direction) F3y=750cos(45)=530.33 N (+y direction) so if i'll put it like your way it would be like (530.33i, 530.33j) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so lets write out full equations out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F _{1}=\left[ 880i510j \right]{\space} kN\] \[F _{2}=\left[ 312.5i541.3j \right]{\space} kN\] \[F _{3}=\left[ 530.3i+530.3j \right]{\space} kN\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, \[F _{R}=\sum_{}^{}F _{i}+\sum_{}^{}F _{j}\]

owlet
 one year ago
Best ResponseYou've already chosen the best response.1add all the x and all the y components Fnet= (162.8i, 520.6j)

owlet
 one year ago
Best ResponseYou've already chosen the best response.1then get the magnitude of Fnet: sqrt( (162.8)^2 + (520.6)^2)=545.5 N or 550 N :D thanks!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F _{R}=(680312.5530.3)i+(510541.3+530.3)j\] \[F _{R}=162.8i+520.6j\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha why did you choose me to do this question? haha

owlet
 one year ago
Best ResponseYou've already chosen the best response.1oops sorry late response. I choose you because you're the only one online that I fanned and you're nice so yeah xD thanks again!
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