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jaylelile
 one year ago
I'm having a hard time remembering how to go about this problem. help? Problem below
jaylelile
 one year ago
I'm having a hard time remembering how to go about this problem. help? Problem below

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jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3well the variables are the same so they are like terms combine them

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3here is an example when the variables and the exponents are the same we can add/subtract their coefficients \[\rm 2x^2+5x^2 = (2+5)x^2=7x^2\]

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 44}{ 40 }^{3}b ?????\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3hmm we didn't add them correctly :=) \[\rm \frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b=(\frac{4^2}{8}+\frac{40^3}{32})b\]

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0that seems too simple though.. lol

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\rm \frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b=(\frac{4^2}{8}+\frac{40^3}{32})b\] \[\rm (\color{ReD}{\frac{4^2}{8}+\frac{40^3}{32}})b\] solve paretheses what's the common denominator ??

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0do we add the exponents?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3no when we `multiply` same bases then we should add their exponents when we combine like terms base stay the same we just have to add/subtract their `coefficients `

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0I'm still getting \[\frac{ 44 }{ 40 }^{3}b\] ..........

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3alright show some work i mean what was your step how did you get 40 at the denominaotr ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3i see what you did there common mistake

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0I just added 8 and 32... is that wrong?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\frac{ 3 }{ 2} + \frac{4}{6}\] dw:1444530347581:dwwrong that's not how we should add

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0then how do we add? I'm lost

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3find common denominator then multiply the numerator of first fraction by the denominator of 2nd fraction multiply the numerator of 2nd fraction by the denominator of first fraction here is an example \[\huge\rm \frac{ a } {\color{Red}{ b} }+\frac{ c }{\color{blue}{ d} } =\frac{ a\color{blue}{d}+c\color{Red}{b} }{ bd}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3to make it easy write factors of 8 and 32 8 = 1 ,2 , 4 , 8 32=1 ,2 ,4 ,8 ,16 ,32 what is the common number ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3brb i need to refresh the page =.=

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3alright sorry i made a mistake there

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3when denominators aren't the same we should multiply them so multiply 8 times 32 that would be the common denominator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3we don't need factors sorry about that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3here is an example \[\huge\rm \frac{ a } {\color{Red}{ b} }+\frac{ c }{\color{blue}{ d} } =\frac{ a\color{blue}{d}+c\color{Red}{b} }{ bd}\] use this example \[\frac{ 4^2 } {\color{Red}{ 8} }+\frac{ 40^3}{\color{blue}{ 32} } \]

jaylelile
 one year ago
Best ResponseYou've already chosen the best response.0so \[\frac{ 44 }{ 256 }^{3}b\] ?????

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3hmm no use the example you can't just add their numerator if the denominators are the same THEN you can just add the numerators \[\frac{3}{\color{Red}{4}}+\frac{5}{\color{blue}{4}} = \frac{3+5}{4}\] in this example both denominators are the same so u can add their exponents

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3but when the denominators arn't the same multiply the numerator of first fraction by the denominator of 2nd fraction multiply the numerator of 2nd fraction by the denominator of first fraction here is an example \[\huge\rm \frac{ a } {\color{Red}{ b} }+\frac{ c }{\color{blue}{ d} } =\frac{ a\color{blue}{d}+c\color{Red}{b} }{ bd}\] same like cross multiplications dw:1444531460579:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3btw you can reduce the fraction before adding them but well let's stik with it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4^2 }{ 8 }+\frac{ 40^3 }{ 32 }=\frac{ 4^3+40^3 }{ 32 }=\frac{ 4^3\left( 1^3+10^3 \right) }{ 32 }\] \[=\frac{ 64\left( 1+1000 \right) }{ 32 }=2\left( 1+1000 \right)=?\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3gtg in few mints so i'll just post this here just like the example i gave u \[\huge\rm \frac{4^2} {\color{Red}{ 8} }+\frac{ 40^3}{\color{blue}{ 32} } =\frac{ 4^2\color{blue}{(32)}+40^3\color{Red}{(8)} }{ 256}\] now you can simplify it
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