jaylelile
  • jaylelile
I'm having a hard time remembering how to go about this problem. help? Problem below
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jaylelile
  • jaylelile
\[\frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b\]
jaylelile
  • jaylelile
@Nnesha ?
Nnesha
  • Nnesha
well the variables are the same so they are like terms combine them

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More answers

Nnesha
  • Nnesha
here is an example when the variables and the exponents are the same we can add/subtract their coefficients \[\rm 2x^2+5x^2 = (2+5)x^2=7x^2\]
jaylelile
  • jaylelile
\[\frac{ 44}{ 40 }^{3}b ?????\]
Nnesha
  • Nnesha
hmm we didn't add them correctly :=) \[\rm \frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b=(\frac{4^2}{8}+\frac{40^3}{32})b\]
jaylelile
  • jaylelile
that seems too simple though.. lol
Nnesha
  • Nnesha
\[\rm \frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b=(\frac{4^2}{8}+\frac{40^3}{32})b\] \[\rm (\color{ReD}{\frac{4^2}{8}+\frac{40^3}{32}})b\] solve paretheses what's the common denominator ??
jaylelile
  • jaylelile
do we add the exponents?
jaylelile
  • jaylelile
I'm so confused
Nnesha
  • Nnesha
no when we `multiply` same bases then we should add their exponents when we combine like terms base stay the same we just have to add/subtract their `coefficients `
jaylelile
  • jaylelile
I'm still getting \[\frac{ 44 }{ 40 }^{3}b\] ..........
Nnesha
  • Nnesha
alright show some work i mean what was your step how did you get 40 at the denominaotr ?
Nnesha
  • Nnesha
i see what you did there common mistake
jaylelile
  • jaylelile
I just added 8 and 32... is that wrong?
Nnesha
  • Nnesha
\[\frac{ 3 }{ 2} + \frac{4}{6}\] |dw:1444530347581:dw|wrong that's not how we should add
jaylelile
  • jaylelile
then how do we add? I'm lost
Nnesha
  • Nnesha
find common denominator then multiply the numerator of first fraction by the denominator of 2nd fraction multiply the numerator of 2nd fraction by the denominator of first fraction here is an example \[\huge\rm \frac{ a } {\color{Red}{ b} }+\frac{ c }{\color{blue}{ d} } =\frac{ a\color{blue}{d}+c\color{Red}{b} }{ bd}\]
Nnesha
  • Nnesha
to make it easy write factors of 8 and 32 8 = 1 ,2 , 4 , 8 32=1 ,2 ,4 ,8 ,16 ,32 what is the common number ??
jaylelile
  • jaylelile
1,2, 4 and 8
Nnesha
  • Nnesha
brb i need to refresh the page =.=
Nnesha
  • Nnesha
alright sorry i made a mistake there
Nnesha
  • Nnesha
when denominators aren't the same we should multiply them so multiply 8 times 32 that would be the common denominator
Nnesha
  • Nnesha
we don't need factors sorry about that
Nnesha
  • Nnesha
here is an example \[\huge\rm \frac{ a } {\color{Red}{ b} }+\frac{ c }{\color{blue}{ d} } =\frac{ a\color{blue}{d}+c\color{Red}{b} }{ bd}\] use this example \[\frac{ 4^2 } {\color{Red}{ 8} }+\frac{ 40^3}{\color{blue}{ 32} } \]
jaylelile
  • jaylelile
so \[\frac{ 44 }{ 256 }^{3}b\] ?????
Nnesha
  • Nnesha
hmm no use the example you can't just add their numerator if the denominators are the same THEN you can just add the numerators \[\frac{3}{\color{Red}{4}}+\frac{5}{\color{blue}{4}} = \frac{3+5}{4}\] in this example both denominators are the same so u can add their exponents
Nnesha
  • Nnesha
but when the denominators arn't the same multiply the numerator of first fraction by the denominator of 2nd fraction multiply the numerator of 2nd fraction by the denominator of first fraction here is an example \[\huge\rm \frac{ a } {\color{Red}{ b} }+\frac{ c }{\color{blue}{ d} } =\frac{ a\color{blue}{d}+c\color{Red}{b} }{ bd}\] same like cross multiplications |dw:1444531460579:dw|
Nnesha
  • Nnesha
make sense hmm ?
Nnesha
  • Nnesha
btw you can reduce the fraction before adding them but well let's stik with it
anonymous
  • anonymous
\[\frac{ 4^2 }{ 8 }+\frac{ 40^3 }{ 32 }=\frac{ 4^3+40^3 }{ 32 }=\frac{ 4^3\left( 1^3+10^3 \right) }{ 32 }\] \[=\frac{ 64\left( 1+1000 \right) }{ 32 }=2\left( 1+1000 \right)=?\]
Nnesha
  • Nnesha
gtg in few mints so i'll just post this here just like the example i gave u \[\huge\rm \frac{4^2} {\color{Red}{ 8} }+\frac{ 40^3}{\color{blue}{ 32} } =\frac{ 4^2\color{blue}{(32)}+40^3\color{Red}{(8)} }{ 256}\] now you can simplify it

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