A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
If a boy on top of a 64 foot tower throws a ball horizontally so that the ball lands 108 feet away. How fast was the ball moving the moment it left his hand?
a)54 feet/sec
b)27 feet/sec
c)108 feet/sec
Please advise,
Thank you
anonymous
 one year ago
If a boy on top of a 64 foot tower throws a ball horizontally so that the ball lands 108 feet away. How fast was the ball moving the moment it left his hand? a)54 feet/sec b)27 feet/sec c)108 feet/sec Please advise, Thank you

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it 108 feet from where the ball was thrown?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444539098522:dw which value is 108?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i will assume that it is 108 feet from where the ball was thrown. (the diagonal)

zephyr141
 one year ago
Best ResponseYou've already chosen the best response.0i'm thinking the 108 feet is the x measurement on your drawing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it is 108ft, its the distance from where it was thrown to the stop

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the first thing you need to do is find the amount of time that the ball will take to each the ground and no matter what the speed, the value will always be the same because the object will fall at a constant rate. To find this time we will need to use our first known which is the height of the tower (64 feet) we will need to convert this to meters to make it easier to solve. 64 feet = 21.333m. the next known is the rate at which it falls 9.8m/s^2. so we can use the equation s=1/2gt^2 or \[t=\sqrt{\frac{ 2s }{ g }}\] and we will get a time of \[t=\sqrt{\frac{ (2)(21.333) }{ 9.8 }}\] t=2.08s. assuming that zephyr is correct then all we need to do is find out what speed the projectile will need to be going in order to hit the ground at 108feet=36m. and speed =distance/time which means speed=36m/2.08s=17m/s. conveerting this to feet/second we get 51.92feet/second.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if (y) was 108 feet you will need to use Pythagoras's theorem to find the bottom displacement.dw:1444540167438:dw \[x=\sqrt{116644096}\] this will be = 86.9feet=29m speed=distance/time=29/2.08=13.94m/s convert it to feet/sec and you get 41.82feet/second.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you it was very well explained! I get it now!! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.