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anonymous

  • one year ago

There are two taps in the bottom of a pool. One tap empties the pool with a speed 2 times more than that of the other tap. The two taps empty the pool in 20 hours. In how many hours the tap with slow speed alone empties the pool?

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  1. imqwerty
    • one year ago
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    let the faster tap empty the pool with a speed of 2L litres/hour the slower tap will empty it with L litres/hour total time to empty the pool=20hrs water taken out by faster tap=2L x 20=40L water taken out by slower tap=Lx 20=20L total volume of pool=40L+20L=60L so now we have total volume =60L and slower tap empties pool @L litres/hour so total time taken by small tap to empty pool=60/L=60hrs

  2. anonymous
    • one year ago
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    no the answer is 40 i thought if the speed of slow tap is V, the speed of faster tap should be 3V cause it says two times more than

  3. imqwerty
    • one year ago
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    ok lets go reverse so it says that the small tap will take 40hrs let the speed of small tap be V so total volume=40V let the speed of fast tap be Y so 40V=20V+20Y 20V=20Y V=Y so this means both taps have same speed but this is not possible :D

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