A community for students.
Here's the question you clicked on:
 0 viewing
Adi3
 one year ago
Will Medal
Please help!!
Use Quadratic formula to solve for x:
(x+2)(x1) = 5
Adi3
 one year ago
Will Medal Please help!! Use Quadratic formula to solve for x: (x+2)(x1) = 5

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Start off by putting into \[ax^2+bx+c=0\] form

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1ok, wait let me solve it first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Good now we have the quadratic formula which is the following \[x = \frac{ b \pm \sqrt{b^24ac} }{ 2a }\] where a = 1, b= 1, and c = 7

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1the answer is 2.15 and 3.15

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1i took the wrong equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x= \frac{ 1 \pm \sqrt{1^24(1)(7)} }{ 2(1) } \implies x = \frac{ 1 \pm \sqrt{29} }{ 2 }\] correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That should \[x \approx 3.19,~~ \text{and}~~ x \approx 2.19\]

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1can i ask you an another quetion pls

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1Use Quadratic formula to solve for x: \[x + \frac{ 1 }{ x+2 } = 4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Same thing as earlier, try putting it into \[ax^2+bx+c=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can multiply through by (x+2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I mean you can find a common denominator which in this case is (x+2) if you like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can do as following \[\frac{ 1 }{ x+2 }=4x \] now you may do as you like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ (x+2) } = (4x)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm, not quite, \[\frac{ 1 }{ (x+2) } = (4x) \implies 1 = (4x)(x+2)\]

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1yeah then we multiply (4x)(x+2) = 4x  x +6

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1an we bring it to the other side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Remember, we want our equation in \[ax^2+bx+c=0\] form, so what you wrote, does that make sense? Think of what you did in the previous problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(4x)(x+2)=1 \implies 4x+8x^22x =1 \implies 2x+8x^2=1 \] so we can set this up as \[x^22x7=0\]

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1ok. sorry i was offline, i had a lag

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1answer is = 1.9, 0.9 right??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you show how you got that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is a, b, and c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x = \frac{ (2) \pm \sqrt{(2)^24(1)(7)} }{ 2(1) } = \frac{ 2 \pm \sqrt{32} }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a = 1, b = 2, c = 7
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.